+3 ....>>>>>>>>..... i have added 20 characters to properly explain my answer
:3
Answer:
The time taken by the airplane to take off, t = 11.46 s
Explanation:
Given data,
The initial velocity of the airplane, u = 24 m/s
The acceleration of the plane, a = 8 m/s
The distance covered until take off, d = 800 m
Using the III equation of motion,
v² = u² +2as
= 24² + 2 x 8 x 800
= 13376
v = 115.65 m/s
Using the first equation of motion,
v = u + at
t = (v-u) / a
= (115.65 - 24) / 8
= 11.46 s
Hence, the time taken by the airplane to take off, t = 11.46 s
Answer:
7.01yard/sec
Explanation:
Given parameters:
Initial position = 50yard
Final position = 12yard
Time = 5.42s
Unknown:
Average speed of runner = ?
Solution:
To solve this problem;
Speed = 
Distance covered = Initial position - final position = 50 - 12 = 38yards
So;
Speed = 
= 7.01yard/sec
The answer is above but I don't know if it's correct.
