Something to do with how the suns magnetic field interacts with the surface plasmas I think.
Answer:
A & B
Explanation:
A & B Would be the right answer since Morse code cannot be represented through the height of the fire.
Answer: Not 100% sure but I think it’s C.
Hope this helps! ^^
Answer:
12164.4 Nm
Explanation:
CHECK THE ATTACHMENT
Given values are;
m1= 470 kg
x= 4m
m2= 75kg
Cm = center of mass
g= acceleration due to gravity= 9.82 m/s^2
The distance of centre of mass is x/2
Center of mass(1) = x/2
But x= 4 m
Then substitute, we have,
Center of mass(1) = 4/2 = 2m
We can find the total torque, through the summation of moments that comes from both the man and the beam.
τ = τ(1) + τ(2)
But
τ(1)= ( Center of m1 × m1 × g)= (2× 470× 9.81)
= 9221.4Nm
τ(2)= X * m2 * g = ( 4× 75 × 9.81)= 2943Nm
τ = τ(1) + τ(2)
= 9221.4Nm + 2943Nm
= 12164.4 Nm
Hence, the magnitude of the torque about the point where the beam is bolted into place is 12164.4 Nm
Answer:
0.0059
Explanation:
According to the question the seismic activity density is given by

Here,
Number of Earthquakes over a given time span = 424
The land area affected = 71300 mi²
So,

The seismic activity density is 0.0059