How do fission nuclear reactions differ from fusion nuclear reactions?
A. Fission reactions involve the conversion of matter into energy, but fusion reactions do not.
B. Fusion reactions involve the conversion of matter into energy, but fission reactions do not.
C. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.
D. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.
Answer:
C
Explanation:
Both fission and fusion are nuclear reactions that produce energy, but their applications differs.
Fission is the splitting of a large (heavy, unstable) nucleus into smaller ones, and fusion is the process where nuclei of small atoms are combine together to form the nuclei of larger atoms releasing vast amounts of energy.
The correct answer is c. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.
The physics of fusion is the process that makes the sun shine, and that makes the hydrogen bomb explode.
Answer:
117.6°
Explanation:
The vertical component of a force directed at some angle α from the vertical is ...
F·cos(α)
We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...
Fw·cos(25°) + Fr·cos(α) = 0
cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030
α ≈ arccos(-0.464030) ≈ 117.6°
Red was pulling at an angle of about 117.6° from the vertical.
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<em>Additional comment</em>
That's about 27.6° below the horizontal.
Answer:
1, 2, 3, and 6 are the answers.
Explanation:
sorry for the late response
Answer:
Step 7- Communicate. Present/share your results. Replicate.
Step 1- Question.
Step 2-Research.
Step 3-Hypothesis.
Step 4-Experiment.
Step 5-Observations.
Step 6-Results/Conclusion
Explanation:
Answer:
y = 10.2 m
Explanation:
It is given that,
Charge, 
It is placed at a distance of 9 cm at x axis
Charge, 
It is placed at a distance of 16 cm at x axis
We need to find the point on the y-axis where the electric potential zero. The net potential on y-axis is equal to 0. So,

Here,

So,

Squaring both sides,

So, at a distance of 10.2 m on the y axis the electric potential equals 0.