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3 years ago

This is a group of elements with few valence electrons that conducts heat and electricity.

Physics

1 answer:

k0ka [10]3 years ago

5 0

Answer:

Metals

Explanation:

The group of elements with few valence electrons that conducts heat and electricity is known metals. Metals are good conductors of heat and electricity. The outer electrons in metals are loosely bound to the atom and are thus able to freely move around and conduct electricity and heat.

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How do fission nuclear reactions differ from fusion nuclear reactions? Fission reactions involve the conversion of matter into e

MakcuM [25]

How do fission nuclear reactions differ from fusion nuclear reactions?

A. Fission reactions involve the conversion of matter into energy, but fusion reactions do not.

B. Fusion reactions involve the conversion of matter into energy, but fission reactions do not.

C. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.

D. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.

Answer:

Explanation:

Both fission and fusion are nuclear reactions that produce energy, but their applications differs.

Fission is the splitting of a large (heavy, unstable) nucleus into smaller ones, and fusion is the process where nuclei of small atoms are combine together to form the nuclei of larger atoms releasing vast amounts of energy.

The correct answer is c. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.

The physics of fusion is the process that makes the sun shine, and that makes the hydrogen bomb explode.

5 0

3 years ago

Read 2 more answers

Red Riding Hood sat down to rest and placed her 1.20-kg basket of goodies beside her. A wolf came along, spotted the basket, and

anygoal [31]

Answer:

117.6°

Explanation:

The vertical component of a force directed at some angle α from the vertical is ...

F·cos(α)

We want the vertical components of the wolf's force (Fw) and Red's force (Fr) to total zero. So for some angle from vertical α, Red's force will satisfy ...

Fw·cos(25°) + Fr·cos(α) = 0

cos(α) = -Fw/Fr·cos(25°) ≈ -(6.4 N)/(12.5 N)·0.906308 ≈ -0.464030

α ≈ arccos(-0.464030) ≈ 117.6°

Red was pulling at an angle of about 117.6° from the vertical.

_____

<em>Additional comment</em>

That's about 27.6° below the horizontal.

3 0

3 years ago

Which lenses are convex? Check all that apply. 1 2 3 4 5 6

Goryan [66]

Answer:

1, 2, 3, and 6 are the answers.

Explanation:

sorry for the late response

5 0

3 years ago

Read 2 more answers

What is the scientific method

MissTica

Answer:

Step 7- Communicate. Present/share your results. Replicate.

Step 1- Question.

Step 2-Research.

Step 3-Hypothesis.

Step 4-Experiment.

Step 5-Observations.

Step 6-Results/Conclusion

Explanation:

4 0

3 years ago

Read 2 more answers

A −3.0 nC charge is on the x-axis at x=−9 cm and a +4.0 nC charge is on the x-axis at x=16 cm. At what point or points on the y-

alexdok [17]

Answer:

y = 10.2 m

Explanation:

It is given that,

Charge, $q_1=-3\ nC$

It is placed at a distance of 9 cm at x axis

Charge, $q_2=+4\ nC$

It is placed at a distance of 16 cm at x axis

We need to find the point on the y-axis where the electric potential zero. The net potential on y-axis is equal to 0. So,

$\dfrac{kq_1}{r_1}+\dfrac{kq_2}{r_2}=0$

Here,

$r_1=\sqrt{y^2+9^2} \\\\r_2=\sqrt{y^2+15^2}$

So,

$\dfrac{kq_1}{r_1}=-\dfrac{kq_2}{r_2}\\\\\dfrac{q_1}{r_1}=-\dfrac{q_2}{r_2}\\\\\dfrac{-3\ nC}{\sqrt{y^2+81} }=-\dfrac{4\ nC}{\sqrt{y^2+225} }\\\\3\times \sqrt{y^2+225}=4\times \sqrt{y^2+81}$

Squaring both sides,

$3\times \sqrt{y^2+225}=4\times \sqrt{y^2+81}\\\\9(y^2+225)=16\times (y^2+81)\\\\9y^2+2025=16y^2-+1296\\\\2025-1296=7y^2\\\\7y^2=729\\\\y=10.2\ m$

So, at a distance of 10.2 m on the y axis the electric potential equals 0.

8 0

3 years ago