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Alona [7]
3 years ago
12

Igneous rocks are formed from

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

heat and pressure

Explanation:

because it happens under heat and pressure.

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Please indicate which of the compounds will yield postive results for the permanganate, ninhydrin, and ceric ammonium nitrate te
maks197457 [2]

The compounds will yield Positive results for the permanganate, ninhydrin, and ceric ammonium nitrate tests  are

permanganate test= ethene,

ninhydrin=aspasyic acid Phenylalanine

ceric ammonium nitrate test= methanol

<h3>What is a compound?</h3>

Generally, A compound is simply defined as a substance made up of two or more different chemical elements held together by chemical bonds that are difficult to break.

In conclusion, For the permanganate test= ethene,

ninhydrin=aspasyic acid Phenylalanine

ceric ammonium nitrate test= methanol

Read more about Compound

brainly.com/question/704297

3 0
2 years ago
A piston is pressurized to 15.5 psi at 405 K. If the piston compresses the air, from 8.98 L to 7.55 L, and the pressure drops to
masya89 [10]

Answer:

239.45 K

Explanation:

Ideal gas law formula is P1V1T2=P2V2T1

Rearrange that to get...

T2=T1P2V2/P1V1

Fill in the values and solve.

7 0
2 years ago
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
Anton [14]

Answer:-  2.4 mol NO_2 .

Solution:- It asks to calculate the moles of NO_2 formed when 1.2 moles of N_2O_5 are reacted.

There is 2:4 mol ratio between N_2O_5 and NO_2 . So, the moles of reactant are multiplied by the mol ratio to get the moles of NO_2 . The calculations are shown below:

1.2mol N_2O_5(\frac{4mol NO_2}{2mol N_2O_5})

= 2.4 mol NO_2

So, 2.4 moles of NO_2 are formed when 1.2 moles of  N_2O_5 were reacted.

7 0
3 years ago
Read 2 more answers
If 10.57 g of magnesium reacts completely with 6.96 g of oxygen, what is the percent by mass of oxygen in magnesium oxide? Round
Deffense [45]

Answer:

39.7 %

Explanation:

magnesium + oxygen ⟶ magnesium oxide

   10.57 g         6.96 g               17.53 g

According to the <em>Law of Conservation of Mass</em>, the mass of the product must equal the total mass of the reactants.

Mass of MgO = 10.57 + 6.96

Mass of MgO = 17.53 g

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this case,

% O = mass of O/mass of MgO × 100 %

Mass of O = 6.96 g

Mass of MgO = 17.53 g

% O = 6.96/17.53 × 100

% O = 0.3970 × 100

% O = 39.7 %

5 0
3 years ago
Question 5(Multiple Choice Worth 3 points)
Travka [436]

Answer: B. Stay the same

8 0
3 years ago
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