10 is 287.9999 m squared and 11 is 2,435.125 yards squared
Answer: a) 4.6798, and b) 19.8%.
Step-by-step explanation:
Since we have given that
P(n) = 
As we know the poisson process, we get that

So, for exactly one car would be
P(n=1) is given by

Hence, our required probability is 0.2599.
a. Approximate the number of these intervals in which exactly one car arrives
Number of these intervals in which exactly one car arrives is given by

We will find the traffic flow q such that

b. Estimate the percentage of time headways that will be 14 seconds or greater.
so, it becomes,

Hence, a) 4.6798, and b) 19.8%.
Answer:
110 grams
Step-by-step explanation:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams.
lowkey hope this helped you, good luck whatever you need it for Imaooo
3 out of 25 = 12 out of 100
3 out of 50 = 6 out of 100
2 out of 25 = 8 out of 100
12 + 6 + 8 = 26
100 - 26 = 74%
Answer: Plan A is less expensive for 50 minutes. About $6 less than Plan B
At 200 minutes, both plans cost $24
Step-by-step explanation:
1.) Look at the numbers for minutes going across the bottom from left to right. Find 50. Follow the grid line up to where the blue line crosses it. (The blue line is lower than the red line so the cost is less.) Look at the numbers on the cost scale to verify the difference if someone asked. Plan A costs $6. Plab B costs $12 for 50 minutes.
2.) Look at where the Red and Blue lines intersect. That is where the plans cost the same amount of money for the same amount of minutes. Follow the grid line down from that point to find the number of minutes.