Given: Normal pull of gravity g = 9.8 m/s²;
g = 0.855 m/s² (at a certain distance)
Universal gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²
Mass of the Earth Me = 5.98 x 10²⁴ Kg
Radius r = ?
g = GMe/r²
r = √GMe/g
r = √(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)/(0.855 m/s²)
r = 2.16 x 10⁷ m or
r = 21,610 Km
.
hydrological cycle is primarily driven by solar energy
Answer:
0.932 m/h
Explanation:
Parameters given:
Distance walked by couple, D = 1.5 km
Time spent in walking, t = 60 min
To solve this we simply apply the formula for average peed:
Average Speed = total distance / total time taken
The question asks specifically to put the answer in miles per hour (m/h), hence, we need to convert the distance to miles and the time to hours:
Distance in miles:
1 km = 0.622 miles
1.5 km = 1.5 * 0.622 = 0.932 miles
Time in hours = 60 / 60 = 1 hour
Hence, the speed is:
Speed = 0.932 / 1 = 0.932 m/h
The average speed of the couple is 0.932 m/h
