1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grigory [225]
3 years ago
12

A 12.0-g cd with a radius of 5.81 cm rotates with an angular speed of 33.2 rad/s. what is its kinetic energy?

Physics
1 answer:
schepotkina [342]3 years ago
4 0
Use the formula 1/2*I*w^2 where w is the angular speed and I is the rotaional inirtia (for disk it is .5*mass*radius^2).
You might be interested in
Astronomers have proposed the existence of an unexplained force that is causing the expansion of the universe to accelerate. Wha
Alik [6]
4. Dark Energy. This is the mysterious force causing the expansion of space. No one has ever seen this force.
4 0
3 years ago
Read 2 more answers
Can you think of a scenario when the kinetic and gravitational potential energy could both be zero ? Describe or draw how this c
Inga [223]

Both kinetic and gravitational potential energy can become zero at infinite distance from the Earth.

Consider an object  of mass <em>m </em>projected from the surface of the Earth with a velocity <em>v. </em>

The total energy of the body on the surface of the Earth is the sum of its kinetic energy \frac{1}{2} mv^2and gravitational potential energy -\frac{GMm}{R^2}.

here, <em>M</em> is the mass of the Earth, <em>R</em> is the radius of Earth and <em>G</em> is the universal gravitational constant.

The gravitational potential energy of the object is negative since it is in an attractive field, which is the gravitational field of the Earth.

The energy of the object on the surface of the earth is given by,

E_i=\frac{1}{2} mv^2-\frac{GMm}{R^2}

As the object rises upwards, it experiences deceleration due to the gravitational force of the Earth. Its velocity decreases and hence its kinetic energy decreases.

The decrease in kinetic energy is manifested as  an equal increase in potential energy. The potential energy becomes less and less negative as more and more kinetic energy is converted into potential energy.

At a height <em>h</em> from the surface of the Earth, the energy of the object is given by,

E_h=\frac{1}{2} mv_h^2-\frac{GMm}{(R+h)^2}

The velocity v_h is less than <em>v</em>.

When h =∞, the gravitational potential energy increases from a negative value to zero.

If the velocity of projection is adjusted in such a manner that the velocity decreases to zero at infinite distance from the earth, the object's kinetic energy also becomes equal to zero.

Thus, it is possible for both kinetic and potential energies to be zero at infinite distance from the Earth. In this case, kinetic energy decreases from a positive value to zero and the gravitational potential energy increases from  a negative value to zero.


7 0
3 years ago
How do streams change as they flow from mountains down to plains? Plz help URGENT I need it today
lisov135 [29]
They start as one stream, then get curvier, then empy into a delta. A delta is a ton of streams of water. It is one, then empties out into a ton of streams.
~Deceptiøn

5 0
3 years ago
Calculate the magnitude of the gravitational force between Goku with a mass of 62 kg and King Kai’s planet with a mass of 1.458x
Brilliant_brown [7]

Answer:

6227.866 N

Explanation:

F = G . m(goku) . m(planet) / d²

F = 6.674 x 10-¹¹ x 62 x 1.458 . 10¹⁵ / 31²

F = 6227.866 N

7 0
3 years ago
A 27.0 g marble sliding to the right at 56.8 cm/s overtakes and collides elastically with a 13.5 g marble moving in the same dir
Nataly [62]

Answer:v_1=28.4 cm/s

Explanation:

Given

mass of marble m_1=27 gm

velocity of marble u_1=56.8 cm/s \approx 0.568 m/s

mass of second marble m_2=13.5 gm

Velocity of second marble u_2=14.2 cm/s \approx 0.142 m/s

After collision 13.5 gm marble moves to the right  at i.e. v_2=71 cm/s

Conserving momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71

1533.6+191.7=27\cdot v_1+958.5

27\cdot v_1=766.8

v_1=\frac{766.8}{27}=28.4 cm/s

7 0
3 years ago
Other questions:
  • To maintain a constant speed, the force provided by a car's engine must equal the drag force plus the force of friction of the r
    10·1 answer
  • Why does a liquid need a container and a solid doesn't?
    5·1 answer
  • If any problem involving circular motion, which way does the acceleration vector point ?
    10·1 answer
  • the mass of a car is 1000 kg. how much force would be required to accelerate the car at a rate of 3 m/s^2
    13·2 answers
  • A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues
    13·2 answers
  • A current of 0.2A flows through a component with a resistance of 40ohms calculate the potential difference
    5·1 answer
  • What is the name of the compound br8P4
    14·1 answer
  • 3. One cubic metre is equal to​
    12·1 answer
  • A slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the botto
    15·1 answer
  • even though the sun is so much bigger than the moon, why does the moon have a stronger effect on tides?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!