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3 years ago

An automobile traveling along a straight road

Physics

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

t = 2.97[s]

Explanation:

To solve this problem we must use the following kinematics equations, we must bear in mind that the positive sign of the acceleration value means that the car is increased its speed.

$v_{f}^{2} =v_{o}^{2} +(2*a*(x-x_{o} ))$

where:

x - xo = 180 [ft]

a = acceleration [ft/s^2]

Vo = initial velocity = 53 [ft/s]

Vf = final velocity = 68 [ft/s]

Now replacing we find:

(68^2) = (53^2) + (2*a*180)

a = 5.04 [ft/s^2]

Now using the following equation:

$v_{f}=v_{0}+a*t$

68 = 53 + (5.04*t)

t = (68 - 53)/5.04

t = 2.97[s]

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Help please It’s kinda urgent

user100 [1]

Answer:

a = - 50 [m/s²]

Explanation:

To solve this problem we simply have to replace the values supplied in the given equation.

Vf = final velocity = 0.5 [m/s]

Vi = initial velocity = 10 [m/s]

s = distance = 100 [m]

a = acceleration [m/s²]

Now replacing we have:

$(0.5)^{2}-(10)^{2} = 2*a*(100)\\0.25-10000=200*a\\200*a=-9999.75\\a =-50 [m/s^{2} ]$

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2 years ago

What is the dimensional formula of young modulas

LekaFEV [45]

Answer:

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3 years ago

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Ksivusya [100]

The situation (heat going through the ceiling) describes
conduction ... heat going from one place to another by
soaking through some material.

A). This is the one. Heat goes from from the marshmallow
to your hand by soaking through the wire. This is conduction too.

B). No. The heat in the room goes from the floor to the ceiling
because the warm air rises and carries it there. This is convection.

C). No. There's nothing for the heat to soak through between
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3 years ago

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A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of

Gennadij [26K]

To solve this problem we will apply the concepts related to the electric field such as the smelting of the Force and the load (In this case the force is equivalent to the weight). Later we will apply the ratio of the total charge as a function of the multiplication of the number of electrons and their individual charge.

$E = \frac{mg}{q}$

Here,

m = mass

g = Acceleration due to gravity

Rearranging to find the charge,

$q = \frac{mg}{E}$

Replacing,

$q = \frac{(3.37*10^{-9})(9.8)}{11000}$

$q = 3.002*10^{-12}C$

Since the field is acting upwards the charge on the drop should be negative to balance it in air. The equation to find the number of electrons then is

$q = ne$