Answer:
a. Your mass with the basketball is 55.5 kg
b. Your new velocity is 0.045 m/s
Explanation:
We first add your weight and the basketballs weight to get 55.5 kg.
Then to find b. we use the equation: v final = (m1 * v1) / (m1 +m2)
So m1 is the basketball which is 0.5 kg and v1 is 5 m/s. So the top half is (0.5 * 5)
The bottom half is just our weights added together.
Answer:
where is the box? ehh bring the box out
Answer:
ΔL=0.14m
Explanation:
The period of oscillations of simple pendulum is
Here L is length of pendulum and g is acceleration due to gravity
So the length of pendulum is:
So increase in length is:
ΔL=L₂-L₁
![=\frac{T_{2}^{2}g }{4 \pi^{2} }-\frac{T_{1}^{2}g }{4 \pi^{2} }\\=\frac{g}{4 \pi^{2} }[T_2^{2} -T_1^{2} ]\\ =\frac{9.8}{4 \pi^{2}}[(1.15+0.22)^{2}-(1.15)^{2} ] \\=0.14m](https://tex.z-dn.net/?f=%3D%5Cfrac%7BT_%7B2%7D%5E%7B2%7Dg%20%7D%7B4%20%5Cpi%5E%7B2%7D%20%7D-%5Cfrac%7BT_%7B1%7D%5E%7B2%7Dg%20%7D%7B4%20%5Cpi%5E%7B2%7D%20%7D%5C%5C%3D%5Cfrac%7Bg%7D%7B4%20%5Cpi%5E%7B2%7D%20%7D%5BT_2%5E%7B2%7D%20-T_1%5E%7B2%7D%20%5D%5C%5C%20%3D%5Cfrac%7B9.8%7D%7B4%20%5Cpi%5E%7B2%7D%7D%5B%281.15%2B0.22%29%5E%7B2%7D-%281.15%29%5E%7B2%7D%20%20%5D%20%5C%5C%3D0.14m)
ΔL=0.14m
Almost 3 times fast than normal pulley system
mark me
Answer: 0.013 seconds
Explanation:
Given that
Mass of golf ball = 0.058 kg
Force = 272 N
Velocity = 62.0 m/s
Time taken = ?
Recall that force is the rate of change of momentum per unit time
i.e Force = Change in momentum / Time
i.e Force = (Mass x velocity) / Time
272N = (0.058 kg x 62.0 m/s) / Time
272N = 3.6kgm/s / Time
Time = (3.6kgm/s / 272N)
Time = 0.013 seconds
Thus, the ball was in contact with the club for 0.013 seconds
