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Anvisha [2.4K]
3 years ago
10

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base. Use patterns in the periodic table to e

xplain why the substances you identified acted as the acid and the base in this reaction.
Physics
1 answer:
Oliga [24]3 years ago
6 0

A conjugate acid is formed from the base  by accepting a proton from the acid .

A conjugate base is obtained from the Brownstead - Lowry acid when it looses a proton while the conjugate acid is obtained from the Brownstead - Lowry base when it accepts a proton. In the Brownstead - Lowry sense, acid base reaction involves the loss or gain of a proton.

Consider the hypothetical reaction; AH + :B ⇄ BH + :A. The specie BH is the conjugate acid while the specie  :B is the  Brownstead - Lowry base . The specie :A is the conjugate base while the specie AH is the  Brownstead - Lowry acid.

Learn more about conjugate acid: brainly.com/question/10468518

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According to aristotle what kind of motion requires no force
Ivan

natural motion is the motion that requires no force

3 0
4 years ago
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
A home uses ten 100-watt lightbulbs for five hours per day. Approximately how many kilowatt-hours of electrical energy are consu
timurjin [86]

The electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

The given parameters:

  • Number of light bulbs = 10
  • Power consumed by each bulb = 100 W
  • Time of energy consumption, t = 1 year

<h3>What is electrical energy?</h3>

This is the electric power consumed or dissipated at a given period of time.

The  electrical energy consumed in one year by using the light bulbs is calculated as

E = Pt

E = (100 \times 10) \times (1 \ yr \times \frac{8760 \ hrs}{1 \ yr} )= 8,760,000 \ W att-hours\\\\&#10;E = \frac{8,760,000 }{1000} = 8,760 \ kWh

Thus, the electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

Learn more about electrical energy here: brainly.com/question/60890

4 0
2 years ago
According to the diagram of the electromagnetic spectrum shown, what would best represent the
iren2701 [21]

The  best represent the size of visible light will be C. Protozoa

The electromagnetic spectrum, gives the overall distribution of electromagnetic radiation by the  frequency or wavelength. All EM waves travel at the speed of light in a vacuum, but over a wide range of frequencies, wavelengths, and photon energies.

Visible light wavelengths cover the range of approximately 0.4 to 0.7 μm. electromagnetic spectrum that the human eye can see is the Visible light. Visible light is a form of electromagnetic (EM) radiation, along with radio waves, infrared, ultraviolet, X-rays, and microwaves. the wavelengths that are visible to most human eyes is generally known as Visible light

the best represent the size of visible light is Protozoa, According to the diagram of the electromagnetic spectrum shown,

Learn more about electromagnetic spectrum here brainly.com/question/25847009

#SPJ9

6 0
1 year ago
A planet is 15 light years from earth. At which of the following speeds will the crew of a spaceship complete the trip to the pl
Svetradugi [14.3K]

Answer:

option c) 0.88c is the correct answer

Explanation:

using the Lorrentz equation we have

t=\frac{d}{v}\sqrt{1-(\frac{v}{c})^2}

where,

t = time taken to cover the distance

d = Distance

v = velocity

c = speed of light

given

d = 15 light years

Now,

8years=\frac{15years\times c}{v}\sqrt{1-(\frac{v}{c})^2}

or

(\frac{v}{c})^2\times (\frac{8}{15})^2=1-(\frac{v}{c})^2

or

(\frac{v}{c})^2\times 0.284=1-(\frac{v}{c})^2

or

(\frac{v}{c})^2\times 0.284 + (\frac{v}{c})^2 =1

or

(1.284\times \frac{v}{c})^2 =1

or

(\frac{v}{c}) =\sqrt{\frac{1}{0.284}}

or

v=0.88c

7 0
3 years ago
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