Answer:
79.91 g
Explanation:
First we <u>calculate the number of moles of 125.00 grams of copper (II) sulfate pentahydrate </u>(CuSO₄·5H₂O), using<em> its molar mass</em>:
- Molar Mass of CuSO₄·5H₂O = (Molar Mass of CuSO₄) + 5*(Molar Mass of H₂O)
- Molar Mass of CuSO₄·5H₂O = 249.68 g/mol
- moles CuSO₄·5H₂O = 125.00 g ÷ 249.68 g/mol = 0.501 mol CuSO₄·5H₂O
In the reaction, CuSO₄·5H₂O turns into CuSO₄.
So now <u>we convert 0.501 moles of CuSO₄ (anhydrous copper (II) sulfate) into grams</u>, using the <em>molar mass of CuSO₄</em>:
- 0.501 mol CuSO₄ * 159.609 g/mol = 79.91 g CuSO₄
Answer:
yes because it is right and because
To find<span> the </span>valence electrons in an atom<span>, identify what group the element is in. An element in group 1A has 1 </span>valence electron<span>. For example, Li is in group 1A, so that means it has one </span>valence electron. If the element is in group 2A, then it has two valence electrons<span>.</span>
Answer:
Potential Energy
Explanation:
Right now, the match is giving off no energy to it's environment.
<em>Light</em><em> </em><em>it</em><em>.</em>
Now it's giving off a few kinds:
- Thermal energy (heat)
- Light energy
The match has the potential to have energy, but it currently has none.
Answer:
Ionic compounds, such as sodium chloride, are also highly soluble in water. Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.
Explanation: