A young deer needs cell division to grow to its full size. However, a deer's cells continue to divide through its whole life. Wh
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<u>Answer:</u> The mass of nonahydrate iron (III) nitrate is 16.2 g
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of = 0.0020 M
Volume of solution = 2 L
Putting values in above equation, we get:
The chemical equation for the decomposition of hydrated iron (III) nitrate follows:
By Stoichiometry of the reaction:
1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate
So, 0.04 moles of iron (III) nitrate will be produced from = of hydrated iron (III) nitrate
To calculate the mass from given number of moles, we use the equation:
Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol
Moles of nonahydrate iron (III) nitrate = 0.04 moles
Putting values in above equation, we get:
Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g