All categories

3 years ago

Stick a fork into each end of the root vegetable as shown. The forks should be on the same side of the vegetable, and

Physics

1 answer:

zhuklara [117]3 years ago

7 0

Answer:

Yes

Explanation:

There is a position that works better than this and that is switching the sides of the forks.

You might be interested in

A bird lands on a bare copper wire carrying a current of 51

nirvana33 [79]

The resistance of the piece of wire is
$R= \frac{\rho L}{A}$
where
$\rho = 1.68 \cdot 10^{-8}\Omega m$ is the resistivity of the copper
$L=5.1 cm=0.051 m$ is the length of the piece of wire
$A=0.13 cm^2 = 0.13 \cdot 10^{-4} m^2$ is the cross sectional area of the wire
By substituting these values, we find the value of R:
$R= \frac{\rho L}{A}=6.6 \cdot 10^{-5} \Omega$

Then, by using Ohm's law, we find the potential difference between the two points of the wire:
$V=IR=(51 A)(6.6 \cdot 10^{-5} \Omega )=3.4 \cdot 10^{-3} V$

7 0

3 years ago

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i

svet-max [94.6K]

Answer:

$0.261\ \text{m}$

Explanation:

$\Delta f$ = Change in frequency = 2.1 Hz

$f$ = Frequency of source of sound = 440 Hz

$v_m$ = Maximum of the microphone

$v$ = Speed of sound = 343 m/s

$T$ = Time period = 2 s

We have the relation

$\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}$

Amplitude is given by

$A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}$

The amplitude of the simple harmonic motion is $0.261\ \text{m}$ .

4 0

2 years ago

You walk 20 m north then 30 m west for a total timer four minutes what is the magnitude of your average velocity in (m/s)

Shalnov [3]

Answer:

The average velocity is 0.15 m/s

Explanation:

Use the definition of average velocity as the distance traveled divided the time it took.

Since the movement was on the plane from the origin (0, 0) to the point (-30, 20) corresponding to 30 m west and 20 m north, we calculate the distance using the distance between two points on the plane:

$distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} = \sqrt{(-30)^2+20^2} =\sqrt{1300} \approx 36.06\,\,m$

Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.

Then the average velocity becomes:

$v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s$