What angle is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity in half?
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Remember Coulomb's law: the magnitude of the electric force F between two stationary charges q₁ and q₂ over a distance r is
where k ≈ 8,98 × 10⁹ kg•m³/(s²•C²) is Coulomb's constant.
8.1. The diagram is simple, since only two forces are involved. The particle at Q₂ feels a force to the left due to the particle at Q₁ and a downward force due to the particle at Q₃.
8.2. First convert everything to base SI units:
0,02 µC = 0,02 × 10⁻⁶ C = 2 × 10⁻⁸ C
0,03 µC = 3 × 10⁻⁸ C
0,04 µC = 4 × 10⁻⁸ C
300 mm = 300 × 10⁻³ m = 0,3 m
600 mm = 0,6 m
Force due to Q₁ :
Force due to Q₃ :
8.3. The net force on the particle at Q₂ is the vector
Its magnitude is
and makes an angle θ with the positive horizontal axis (pointing to the right) such that
where we subtract 180° because terminates in the third quadrant, but the inverse tangent function can only return angles between -90° and 90°. We use the fact that tan(x) has a period of 180° to get the angle that ends in the right quadrant.
Answer:
All of the statements are correct
Explanation:
Hello!
All of the statements are rigth. You can know this by examining the Lorentz Force:
a )
The dependence on the charge sign can be inferrend by the term q which is the particle's charge. If it changes sign, the force also does.
b)
Although we usually deal with constant magntic Fields, they could also be position dependent, for example the magnetic field of a wire. The fild of teh force will also inherit this position dependence, that is:
c)
d)
Again, from the equation of the force or Lorentz force, we can see that this statement is true.
d)
The validity of this statement is given by the cross product between the velocity (which points twoards the direction of motion of the particle) and the magnetic field