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4 years ago

What angle is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity in half?

Physics

1 answer:

cricket20 [7]4 years ago

8 0

Answer:

45 degree

Explanation:

Let the initial intensity is Io and the angle between the polarizer and the axis of filter is θ.

The intensity of light passing after filter is 0.5 Io.

By using the law of Malus,

$I=I_{0} Cos^{2}\theta$

$0.5I_{0}=I_{0} Cos^{2}\theta$

$0.5= Cos^{2}\theta$

$0.707= Cos\theta$

θ = 45 degree

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How do i calculate this?

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3 years ago

. a boat can travel in still water. (a) if the boat points directly across a stream whose current is what is the velocity (magni

mixer [17]

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Here it is given that the speed of the boat (x) = 2.20m/s

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1 year ago

A pulley system lifts a 1345 n weight a distance of 0.975m. Paul pulls the rope a distance of 3.90m, exerting a force of 375N. A

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A. IMA: 4

The Ideal Mechanical Advantage (IMA) is given by:

$IMA = \frac{d_i}{d_o}$

where

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$d_o$ is the output distance

For the pulley system in this problem, $d_i = 3.90 m$ and $d_o = 0.975 m$ , so the IMA is

$IMA=\frac{3.90 m}{0.975 m}=4$

B. MA: 3.59

The actual mechanical advantage (AMA), or simply the Mechanical Advantage (MA), is given by

$MA=\frac{F_o}{F_i}$

where $F_o$ is the output force and $F_i$ is the input force. For the pulley system in this problem, $F_i = 375 N$ and $F_o = 1345 N$ , so the MA is

$MA=\frac{1345 N}{375 N}=3.59$

C. Efficiency: 89.8 %

The efficiency of a machine is equal to the ratio between the MA and the AMA:

$\eta = \frac{MA}{AMA} \cdot 100$

Therefore, in this case,

$\eta=\frac{3.59}{4}\cdot 100=0.898=89.8 \%$

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3 years ago

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3 years ago

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