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Troyanec [42]
3 years ago
11

What angle is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity in half?

Physics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

45 degree

Explanation:

Let the initial intensity is Io and the angle between the polarizer and the axis of filter is θ.

The intensity of light passing after filter is 0.5 Io.

By using the law of Malus,

I=I_{0} Cos^{2}\theta

0.5I_{0}=I_{0} Cos^{2}\theta

0.5= Cos^{2}\theta

0.707= Cos\theta

θ = 45 degree

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belka [17]

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2 years ago
Can somebody please help
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The amplitude of the wave on the given sinusoidal wave graph is 10 cm.

<h3>What is amplitude of wave?</h3>

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Learn more about wave amplitude here: brainly.com/question/25699025

5 0
2 years ago
In the Olympic shot-put event, an athlete throws the shot with an initial speed of 12.0 m/s at a 40.0 ∘ angle from the horizonta
Gre4nikov [31]

Answer:

Explanation:

given,

initial speed of the shot = 12.0 m/s

angle = 40°

height at which shot leaves her hand = 1.80 m

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v_y = 12 sin 40° = 7.71 m/s

time to reach maximum height =

     = \dfrac{v_y}{g}

     = \dfrac{7.71}{9.8}

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d = vₓ t

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8 0
3 years ago
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