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Troyanec [42]
4 years ago
11

What angle is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity in half?

Physics
1 answer:
cricket20 [7]4 years ago
8 0

Answer:

45 degree

Explanation:

Let the initial intensity is Io and the angle between the polarizer and the axis of filter is θ.

The intensity of light passing after filter is 0.5 Io.

By using the law of Malus,

I=I_{0} Cos^{2}\theta

0.5I_{0}=I_{0} Cos^{2}\theta

0.5= Cos^{2}\theta

0.707= Cos\theta

θ = 45 degree

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Um corpo de massa igual a 2kg move-se com velocidade constante num plano horizontal sem atrito, conforme a figura. Em seguida, e
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Two horses are side by side on a carousel. Which has a greater tangential speed the one closer to the center or the one farther
photoshop1234 [79]

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The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.

Explanation:

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3 years ago
8. At what position does the mass have the greatest acceleration?
gulaghasi [49]

Answer:

Option (e)

Explanation:

If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.

In simple harmonic motion, velocity of the mass will be maximum, kinetic energy is maximum and acceleration is 0 at equilibrium position (at 0 position).

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Therefore, Option (e) will be the answer.

6 0
3 years ago
A coin is placed on a large disk which rotates uniformly at a rate of 1 rot/s. The coefficient of friction between the coin and
s2008m [1.1K]

Answer:

r = 0.02 m

Explanation:

from the question we have :

speed = 1 rps = 1x 60 = 60 rpm

coefficient of friction (μ) = 0.1

acceleration due to gravity (g) = 9.8 m/s^{2}

maximum distance without falling off (r) = ?

to get how far from the center of the disk the coin can be placed without having to slip off we equate the formula for the centrifugal force with the frictional force on the turntable force

mv^2 / r =  m x g x μ

v^2 / r =  g x μ  .......equation 1

where

velocity (v) = angular speed (rads/seconds) x radius

angular speed (rads/seconds) = (\frac{2π}{60} ) x rpm

angular speed (rads/seconds) = (\frac{2 x π}{60} ) x 60 = 6.28 rads/ seconds

now

velocity = 6.28 x r = 6.28 r

now substituting the value of velocity into equation 1

v^2 / r =  g x μ

(6.28r)^2 / r = 9.8 x 0.1

39.5 x r = 0.98

r = 0.02 m

6 0
3 years ago
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