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mylen [45]
2 years ago
15

What reaction/soccur between an acid and base.

Physics
2 answers:
Elena-2011 [213]2 years ago
6 0

Answer:

neutralization reaction

Explanation:

The reaction of an acid with a base is called a neutralization reaction.

quester [9]2 years ago
4 0

es una reacción química que ocurre entre un ácido y una base produciendo sal y agua. ... Se mezcla un ácido fuerte con una base fuerte: Cuando esto sucede, la especie que quedará en disolución será la que esté en mayor cantidad respecto de la otra.

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According to Kepler, what do all bodies in orbit around another have in common?
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All follow an elliptical path that has two foci, rather than a circular path.

Kepler found paths are elliptical, not circular
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3 years ago
An atom of arsenic has how many electron-containing orbitals
irina [24]

Answer:

The Arsenic has three electron-containing orbitals. The orbitals s, p and d.

Explanation:

Arsenic is an element with an atomic number equal of 33, it means that it has 33 electrons in its orbitals in the following way:

1s^{2}

2s^{2}

2p^{6}

3s^{2}

3p^{6}

3d^{10}

4s^{2}

4p^{3}

Therefore, the Arsenic has three electron-containing orbitals (s, p d).

8 0
3 years ago
(this is a question from my leap practice)
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Climatology is a subspecialty of what?
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 Climatology is a subspecialty of Meterology.
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3 years ago
Read 2 more answers
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
3 years ago
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