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hodyreva [135]
3 years ago
5

Could I get help plz

Physics
1 answer:
Sloan [31]3 years ago
3 0

Answer:

440hz

Explanation:

saxophone a plays at 430hz and a frequency of 5 beats per second can be heard so saxophone b is playing at a frequency 10hz louder than saxophone A making it 440hz

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How can an object become charged
morpeh [17]

Answer:

An object gets charged when it's atoms lose or gain an electron to become an ion. For example: ... This means that the fur loses it's electrons to the plastic rod and both objects are now charged. The fur is positively charged because it lost electrons and the rod is negatively charged because it gained electrons

Explanation:

comment how it helps

3 0
3 years ago
Read 2 more answers
In a single-slit diffraction experiment, the width of the slit through which light passes is increased. What happens to the widt
kvasek [131]

Answer:

the width of the central bright fringe reduces

Explanation:

In a single-slit diffraction experiment, if the width of the slit through which light passes is increased, then the width of the central bright fringe reduces.

Example, if the width of the slit is doubled, then the width of the central bright fringe will be halved.

Thus, for single-slit diffraction experiment, increase in the width of the slit through which light passes will result in a corresponding decrease in the width of the central bright fringe.

3 0
3 years ago
Two particles are separated by a certain distance. the force of gravitational interaction between them is f0. now the separation
12345 [234]
 <span>as i recall, gravity is relative to the square of the distance. 

so if the distance is tripled, then the gravitational attraction would be reduced by 3^2 or 1/9. 
so F1 = F0/9 


if the satellite is 2R from the center, and is moved to 4R (doubled would be 3R, tripled is 4R) then the distance is twice, and gravity would be 2^2 or 1/4. 
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4 0
4 years ago
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4. How far apart are a proton and electron if they exert an attractive force of 3 N on one another?
alexandr402 [8]

Answer:

8.76\cdot 10^{-15}m

Explanation:

The magnitude of the electrostatic force between two charges is given by the equation:

F=k\frac{q_1 q_2}{r^2}

where:

k=9\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

And the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

F = 3 N is the force between the proton and the electron

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the charge of the proton and the electron

Therefore, solving for r, we find the separation between the two particles:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(9\cdot 10^9)(1.6\cdot 10^{-19})^2}{3}}=8.76\cdot 10^{-15}m

5 0
3 years ago
PLEASE HELPP
spin [16.1K]

Answer:

Tissue paper

Explanation:

Tissue paper is made from a synthetic material

8 0
3 years ago
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