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andre [41]
2 years ago
8

Please help and show work will be picking brainliest

Chemistry
1 answer:
mojhsa [17]2 years ago
6 0

Answer:

34x4v

Explanation:

ik it is write

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8 0
3 years ago
How many atoms of phosphorus are in 7.00 mol of copper(II) phosphate?
Rama09 [41]

<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is 8.431\times 10^{24}

<u>Explanation:</u>

We are given:

Moles of copper(II) phosphate Cu_3(PO_4)_2 = 7.00 mol

1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms

Moles of phosphorus in copper(II) phosphate = (2\times 7.00mol

According to the mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

So, 7.00 moles of copper(II) phosphate will contain = (2\times 7\times 6.022\times 10^{23}=8.431\times 10^{24} number of phosphorus atoms.

Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is 8.431\times 10^{24}

3 0
3 years ago
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