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marissa [1.9K]
3 years ago
13

R4te me for 10 points and be honest with me PLEASE

Chemistry
2 answers:
Hoochie [10]3 years ago
8 0

Answer:

id give you and 8 or 9 but you are really pretty tho

Explanation:

dezoksy [38]3 years ago
7 0
i give you an 7 i am being honest i was gonna give you a 6 but then your hair is pretty
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How many atoms altogether make up one molecule of glucose ​
lilavasa [31]

Answer:

24 atoms makes altogether a molecule of glucose

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4 years ago
Perform an on-line search to discover what conditions are favourable to the growth of moss. be sure to include a comment on ph c
Genrish500 [490]
Moss can grow abundantly in an environment with favorable conditions. They usually grow abundantly in cool, moist and dark places. If not dark, they prefer shady areas. Also, they tend to grow in acidic soil with pH range between 5.0-5.5. 
4 0
4 years ago
The concentration of hydrogen in soil sample 13 * 10 ^ - 6 * M the soil is tested with a pH meter, what value should the meter r
vovikov84 [41]

Answer:

pH = 4.9

Explanation:

Given data

[H⁺] = 13 × 10⁻⁶ M

The pH is a scale used to determine <em>the acidity or basicity of a solution</em>. The pH is related to the concentration of hydrogen ions through the following expression.

pH = -log [H⁺]

pH = -log 13 × 10⁻⁶

pH = 4.9

Since the pH < 7, the soil is considered to be acid.

6 0
4 years ago
Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate
Vlada [557]
Stoichiometry <span>of the reaction:

</span><span>2 KClO</span>₃<span>    =    2 KCl  +   3 O</span>₂
  ↓                                      ↓
    
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

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= 3 moles de KClO₃

hope this helps!
4 0
3 years ago
Read 2 more answers
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
Rashid [163]

Answer:

Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                       \frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

3 0
3 years ago
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