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3 years ago

R4te me for 10 points and be honest with me PLEASE

Chemistry

2 answers:

Hoochie [10]3 years ago

8 0

Answer:

id give you and 8 or 9 but you are really pretty tho

Explanation:

dezoksy [38]3 years ago

7 0

i give you an 7 i am being honest i was gonna give you a 6 but then your hair is pretty

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An atom is found in group 17 and contains 10 neutrons. How many valence

Naddika [18.5K]

Just 7 electrons this is the answer

8 0

3 years ago

Potasyum-40 küçük atom numaralı doğal radyoaktif birkaç element izotopundan biridir ve doğada K izotopları içerisindeki bolluk y

enot [183]

Answer:

6.707 × 10¹⁷

Explanation:

From the information given:

40 ^ K kütlesi = sütteki K kütlesi × 40 ^ K / 100 kütle yüzdesi

nerede;

sütteki K kütlesi = 1.65 mg of K/mL × 225 mL = 371.25 mg of K

∴

40 ^ K kütlesi = 371.25 × 0.012/100

40 ^ K kütlesi = 0,04455 mg = 4.455 × 10⁻⁵ grams

40 ^ K mol sayısı = 40 ^ K kütlesi / molar kütle

= 4.455 × 10⁻⁵/40

= 1.11375 × 10⁻⁶

Son olarak, 40 ^ K = mol × Avogadro sayısı atomları

= 1.11375 × 10⁻⁶ × 6.022 × 10^23

= 6.707 × 10¹⁷

3 0

3 years ago

What is the mass shown? (Sorry u cant really see!)

Thepotemich [5.8K]

It is the bottom answer. (77.5)

8 0

3 years ago

Which of the following reactions would result in the formation of a gaseous product?

AnnyKZ [126]

Ca(OH)2 + H3PO4
hope it helps

3 0

3 years ago

How many molecules of ethane (C2H6) are present in 0.334 g of C2H6?

zmey [24]

Answer:

6.6253*10²¹molecules of ethane (C₂H₆) are present in 0.334 g of C₂H₆

Explanation:

Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.

In this case, being:

C: 12 g/mole
H: 1 g/mole

the molar mass of ethane C₂H₆ is:

C₂H₆: 2*12 g/mole + 6* 1 g/mole= 30 g/mole

Then you can apply the following rule of three: if 30 grams of C₂H₆ are present in 1 mole, 0.334 grams of C₂H₆ in how many moles are present?

$moles of C_{2} H_{6} =\frac{0.334 grams*1 mole}{30 grams}$

moles of C₂H₆=0.011

Finally, taking into account the definition of Avogadro's number, you can apply the following rule of three: if there are 6.023 * 10²³ molecules of C₂H₆ in 1 mole, how many molecules are there in 0.011 moles?

$molecules of C_{2} H_{6} =\frac{0.011 moles*6.023*10^{23}molecules }{1 mole}$

molecules of C₂H₆= 6.6253*10²¹

6.6253*10²¹molecules of ethane (C₂H₆) are present in 0.334 g of C₂H₆

5 0

3 years ago