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aivan3 [116]
4 years ago
9

Why can a ray be used to represent light in a ray diagram?

Physics
1 answer:
Tomtit [17]4 years ago
7 0

Answer: C

Explanation:

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To calculate the velocity of an object the of the position vs time graph should be calculated
frutty [35]
<span>The vertical axis represents the velocity of the object</span>
3 0
4 years ago
Read 2 more answers
Two violinists are trying to tune their instruments in an orchestra. One is producing the desired frequency of 440.0 hz. The oth
Katyanochek1 [597]

Answer:

Percentage change in tension is 3.8%

Explanation:

We have given initially frequency f_1 = 440 Hz

Let tension in the string at this frequency is T_1

Now second frequency is f_2=448.4Hz

Frequency in string is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu }}

From the relation we can say that

\frac{f_1}{f_2}=\sqrt{\frac{T_1}{T_2}}

\frac{440}{448.4}=\sqrt{\frac{T_1}{T_2}}

{\frac{T_2}{T_1}}=1.038

Percentage change in tension is equal to

=\frac{T_2-T_1}{T_1}=\frac{T_2}{T_1}-1=(1.038-1)\times 100=3.8 %

So percentage change in tension is 3.8%

4 0
3 years ago
Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t
marin [14]

Answer:

Part a)

Q = 952 cal/day

Part b)

P = 46 Watt

Part c)

\Delta P = 54 W

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

m = 5000 kg

Q = 70,000 Cal

so we have energy required per kg

E = \frac{70,000}{5000}

E = 14 cal/kg

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

Q = 68 \times 14

Q = 952 cal/day

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

P = \frac{952 \times 4186}{24\times 3600}

P = 46 Watt

Part c)

resting power given in the book is

P' = 100 W

so this is less than the power given

\Delta P = 100 - 46

\Delta P = 54 W

6 0
3 years ago
A tank contains one mole of carbon dioxide gas at a pressure of 6.70 atm and a temperature of 23.0°C. The tank (which has a fixe
quester [9]

Answer: 888.45 K or 615.3 °c

Explanation:

According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.

P/T = Constant

Therefore, P1/T1 = P2/T2

P1 = 6.7 atm

T1= 23°c = 273.15 + 23 = 296.15K

Since P2 is tripled, then,

P2 = 6.7 x 3= 20.1 atm

T2 = (20.1 x 296.15) ÷ 6.7

T2 = 888.45 K

Or in celcius 615.3°c

5 0
4 years ago
two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignorin
Dovator [93]

Answer:

AFter 3.5 s, the wagon is moving at:   4.62\,\,\frac{m}{s}

Explanation:

Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):

Net force = 250 N + 178 N = 428 N

Therefore, the acceleration from Newton's 2nd Law is:

F=m\,*\,a\\a = \frac{F}{m} \\a= \frac{428}{325}\, \frac{m}{s^2} \\a\approx 1.32 \,\,\frac{m}{s^2}

So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:

v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,\frac{m}{s} \\v_f=4.62\,\,\frac{m}{s}

7 0
3 years ago
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