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yaroslaw [1]
3 years ago
15

The water in a river flows uniformly at a constant speed of 2.27 m/s between parallel banks 69.3 m apart. You are to deliver a p

ackage directly across the river, but you can swim only at 1.58 m/s. (a) If you choose to minimize the time you spend in the water, in what direction should you head? ° from the direction of the stream (b) How far downstream will you be carried? m (c) If you choose to minimize the distance downstream that the river carries you, in what direction should you head? ° from the direction of the stream (d) How far downstream will you be carried?

Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer: Got it!

Explanation: The water in a river flows uniformly at a constant speed of 2.50m/s between two parallel banks 80.0m apart. You are to deliver a package directly across the river, but you can only swim at 1.5m/s.

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An apple is placed 20.0 cm in front of a diverging lens of focal length 10.0 cm. Find the image distance and the magnification o
jenyasd209 [6]

Answer:

Image distance of apple=-6.7 cm

Magnification of apple=0.33

Explanation:

We are given that an apple is placed 20.cm in front of a diverging lens.

Object distance=u=-20 cm

Focal length=f=-10 cm

Because focal length of diverging lens is negative.

We have to find the image distance and magnification of the apple.

Lens formula

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

Substitute the values then we get

-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}

\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}

\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}

v=-\frac{20}{3}=-6.7 cm

Image distance of apple=-6.7 cm

Magnification=m=\frac{v}{u}=\frac{-\frac{20}{3}}{-20}

Magnification of apple=\frac{1}{3}=0.33

Hence, the magnification of apple=0.33

5 0
2 years ago
What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity
san4es73 [151]
1.0 x 10-3 N is the correct answer!
6 0
2 years ago
Read 2 more answers
6. Sandy adds 3 sugar packets to her tea in order to make it sweeter. She stirs in the sugar and then takes a sip. She notices t
irina1246 [14]

Answer:

C.Supersaturated

Explanation:

There are three types of solution:

<u>SATURATED SOLUTION</u>:

It is the solution that contains maximum amount of solute dissolved in a solution in normal conditions.  

<u>UNSATURATED SOLUTION</u>:

It is the solution that contains less than the maximum amount of solute dissolved in a solution in normal conditions. It has space for more solute to be dissolved in it.

<u>SUPERSATURATED SOLUTION:</u>

It contains more than the maximum amount of solute dissolved in it. Such a solution has no capacity to dissolve any more solute under any conditions.

Since the sugar is no more dissolving in the tea and has settled down. Therefore, the solution is:

<u>C.Supersaturated</u>

7 0
2 years ago
Find the work done lifting a 290-pound weight 28 feet in the air.
Nataly [62]
The answer is d.8,120 foot-pounds
6 0
3 years ago
Read 2 more answers
Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an
galben [10]

Answer:

\triangle P=1.95*10^{-4}

Explanation:

Mass m=0.001

Diameter d=1.2m

Length l=10m

Generally the equation for Volume flow rate is mathematically given by

 Q=AV

 V=\frac{Q}{\pi/4D^2}

 V=\frac{0.001}{\pi/4(1.2)^2}

 V=8.84*10^{-4}

Generally the equation for Friction factor is mathematically given by

 F=\frac{64}{Re}

Where Re

Re=Reynolds Number

 Re=\frac{pVD}{\mu}

 Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}

 Re=1040

Therefore

 F=\frac{64}{Re}

 F=\frac{64}{1040}

 F=0.06

Generally the equation for Friction factor is mathematically given by

 Head loss=\frac{fLv^2}{2dg}

 H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}

 H=19.9*10^{-9}

Where

H=\frac{\triangle P}{\rho g}

\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}

\triangle P=H*\rho g

\triangle P=1.95*10^{-4}

 

6 0
3 years ago
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