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Anna11 [10]
3 years ago
3

Chlorhexidine gluconate is available in different products in concentrations of 4% w/v and 0.12% w/v. How many milliliters of th

e more dilute product may be prepared from each fluidounce of the more concentrated product
Chemistry
1 answer:
Reika [66]3 years ago
4 0

Answer:

From each fluidounce, 985.78 milliliters of the more dilute product can be produced.

Explanation:

From the given information:

4% w/v = 4g of solute in 100 mL of solution

0.12% w/v = 0.12g of solute in 100 mL of solution

Since 1 fluidounce = 29.5735 ml

∴

100 mL of solution contains 4g of solute

29.95735 ml will have \dfrac{4}{100} \times 29.5735

= 1.18294g solute

Thus, 1 fluidounce contains 1.18294g solute

So, for the dilute solution, 0.12 g solute yields 100 mL solution

∴ 1.18294g will have \dfrac{100}{0.12} \times 1.18294

= 985.78 ml

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It takes 281.7 kJ of energy to remove 1 mole of electrons from the atoms on the surface of lithium metal. If lithium metal is ir
Alex17521 [72]

Answer:

The maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

Explanation:

We know that total energy

E = \frac{hc}{\lambda}  ------------ (1)

Here h = plank's constant = 6.62 × 10^{-34} J s

c = speed of light = 3 × 10^{8} \frac{m}{s}

\lambda = 261 nm = 261  × 10^{-9} m

Put all these values in equation (1) we get

E = 7.6   × 10^{-19} J

We know that

Total energy = Energy to remove an electron + K.E of electron

Energy to remove an electron = \frac{281.7 (1000)}{(6.023)10^{23} }

Energy to remove an electron = 4.67  × 10^{-19} J

K.E of electron = Total energy - Energy to remove an electron

K.E of electron = 7.6   × 10^{-19} -  4.67  × 10^{-19}

K.E of electron = 2.93 × 10^{-19} Joule

Therefore the maximum kinetic energy of electron is = 2.93 × 10^{-19} Joule

3 0
4 years ago
• An element in group 2, period 4 has similar properties with
babymother [125]

Answer:  Elements in Group 2

Explanation:  The periodic table was arranged by Dmitri Mendeleev specifically  around similarites in their chemical behaviors.  He found that as atomic number increases, at some point an element starts to react in a manner similar to a previous one.  When that happened, he would place the larger element under the smaller one, and eventually noticed a periodicity in the table.  Elements in a column (Groups) had similiar chemical properties.  We know today that these similarities are due to the electron configuration, and that these configurations repeat themselves.  He left gaps in the table when he could find an existing element with properties similar to others in that group.  I big leap of faith, but it worked.  Elements for those missing boxes were eventually discovered.

7 0
3 years ago
In a galvanic cell, electrons are transferred from one half cell to the other as the redox reaction progresses.
tia_tia [17]

the two process that occur in a cell are

oxidation: this is loss of electron by electrode. the metal electrode loaes electrons and get oxidized and forms ions

the ions get migrated to solution


Reduction: here the ions present in solution gains electron and get deposited on electrodes.

so gain of electrons is by ions


electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.



5 0
3 years ago
Read 2 more answers
CuSO4.5H2O(k) ısı CuSO4(k) + 5 H2O(g) eşitliğine göre bakır sülfatın kristal suyu miktarı ve kaba formülü hesaplanacaktır.
baherus [9]

Answer:

159.609 g/mol

Explanation:

According to the CuSO4.5H2O (k) heat CuSO4 (k) + 5 H2O (g) equation, the crystal water amount of copper sulfate and its rough formula will be calculated.

Weight of copper sulfate containing crystal water = m1 = 249.62… g

Weight of copper sulfate without crystal water weighed = m2 = 159.62 g

Accordingly, calculate the x and y values ​​in the molecular formula of copper sulfate (xCuSO4.yH2O).

3 0
3 years ago
Why do you think large differences in temperature between the wet bulb and dry bulb thermometers are possible only at higher tem
olganol [36]

Answer:

This is the temperature indicated by a moistened thermometer bulb exposed to the air flow. The evaporation is reduced when the air contains more water vapor. The wet bulb temperature is always lower than the dry bulb temperature but will be identical with 100% relative humidity.

Explanation:

7 0
3 years ago
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