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Eva8 [605]
3 years ago
7

Help pls! I am begging you pls help me!!!

Physics
2 answers:
aleksley [76]3 years ago
4 0

Answer:

Please see list of answers below

Explanation:

If the FORCE applied to the car doubles, then following the equation F = m * a , the acceleration will DOUBLE as well.

The mass of the car stays the SAME.

And the velocity of the car will INCREASE with time based on the formula of kinematics of an accelerated object:

v(t) = vi + a * t

REY [17]3 years ago
3 0

Answer:

Consider the relationship of the variables in Newton’s second law. In a drag car race, the force applied to the car is doubled by the driver stepping on the gas pedal.

The acceleration of the car will

✔ double

.

The mass of the car will

✔ remain unchanged

.

The velocity of the car will

✔ increase

.

Explanation:

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Answer:

Check body of the explanation

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Ooook, quick theory rushdown. if you're at a depth of h in a tank of a fluid, the pressure is the sum of the atmosferic pressure (if the tank is open on top) plus a term which is the product of acceleration of gravity - about 10 ms^-^2, the density of whatever you're sinking in, and the depth at which you are. In formula, p(h) = p_0 + \rho g h, and the pressure is the same for every point of the tank at the same depth.

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1a. The pressure at A is - not counting atmosferic pressure - 1000 * 10 * 1 = 10^4 Pa, while in B is 1000*10*2 = 2*10^4 Pa, so it's half of it.

1b. The two points are at the same depth, so the pressure is the same - they would be even if the two cilinders weren't linked!

1c. Ditto. Same depth? same pressure!

1d. Usual equation, this time density is 800. Pressure is 800*10*2 = 1,6*10^4 Pa: Since the density is 4/5 of water, the pressure is also 4/5 of the one exerted by water

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2b. Density is defined as mass over volume, so you simply multiply the volume you found earlier by the density of paraffine: 800* 24 = 1,92 *10^4kg

2c. Weight is defined as the mass of something times the acceleration due to gravity, in our case it's 1.92 *10^4 kg * 10 ms^{-2} = 1.92 * 10^5 N

2d. \rho gh again, what a surprise! 800 {kg \over m^3} * 10 {N \over kg}} * 2 m = 1,6* 10^4 {N\over m^2} =1.6*10^4 Pa

3. Yet again, \rho gh. 1000 {kg \over m^3} * 10 {N \over kg}} * 2 m = 2* 10^4 {N\over m^2} =2*10^4 Pa

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