Answer:
.team 1 a = 20.8 m/s² team 2 a = 19.2 m/s²
Explanation:
Let's use Newton's second law to calculate the acceleration of the two groups
F = ma
a = F / M
Group 1
a = 9 1354/9 65
a = 20.8 m / s²
Group 2
a = 9 1364/9 71
a = 19.2 m / s²
If the two groups pull against each other, group 1 should win, by creating a greater acceleration.
Δa = 20.8 -19.2
Δa = 1.6 m / s²
You use long division.
Find the largest number whose square is less than or equal to the number in the leftmost group (55 < 30 < 66). Take this number as the divisor and the quotient with the number in the leftmost group as the dividend (30). Divide and get the remainder (5 in this case).
Bring down the next pair 58. Add the divisor with the quotient and enter it with a blank on its right. Guess a largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend. In this case 105 × 5 = 525, so we choose the new digit as 5. Get the remainder.
Bring down the next pair 09. Add the divisor with the quotient and enter it with a blank on its right. Guess a largest possible digit to fill the blank which will also become the new digit in the quotient, such that when the new divisor is multiplied to the new quotient the product is less than or equal to the dividend. In this case 1103 × 3 = 3309, so we choose the new digit as 3. Get the remainder.
Put the decimal point.
End of division (Remainder is 0 and next digit after decimal is 0).
√305809 = 553
Answer:
I think its b lol correct me if I'm wrong
Answer:
- Work done is maximum when the movement of object is in line and direction of force.
OR
- Work done is maximum, when displacement takes place along the direction of force.
- Work done is given by the equation
W = F.S
<em> W = F. S cos Θ</em>
<em>When cos Θ = 0° ; cos 0 = 1</em>
