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RSB [31]
3 years ago
5

The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at

t=20s?
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

θ = 20.9 rad

Explanation:

In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship

           w = θ / t

           θ = w t

if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians

suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system

          w = 10 rpm (\frac{2\pi  rad}{1 rev}) ( \frac{1 min}{60 s} )

= 1,047 rads

let's calculate

          θ = 1,047 20

          θ = 20.9 rad

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Which part of a laser printer applies a positive charge to the paper that attracts the toner particles to it
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The part of laser printer that applies a positive charge to the paper in order to attract the toner particles is known as transfer roller.

<h3 />

What is a laser printer:

A laser printer is a kind of printer that uses the electrostatic digital printing process to perform printing. It makes use of the static electricity and toner powder in place of liquid ink.

The toner is applied to specific areas which are dependent on the charge difference created or on the static electricity.

Following are the components of a laser printer:

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        This unit of a laser printer generally consists of a laser diode, a

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  • Cartridge unit:

        This unit of laser printer consists of three drums, namely primary

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  • Fuser assembly unit:

        This unit of laser printer consists of a pressure roller and a fuser                roller, where the fuser roller assembly consists of a heating

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Therefore, the transfer roller unit of a laser printer applies a positive charge to the paper that attracts the toner particles to it.

Learn more about laser printers here:

<u>brainly.com/question/5039703</u>

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