How many atoms of nitrogen are in Fe2(NO4)2?
1 answer:
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Answer : The energy released by an electron in a mercury atom to produce a photon of this light must be,
Explanation : Given,
Wavelength =
conversion used :
Formula used :
As,
So,
where,
= frequency
h = Planck's constant =
= wavelength =
c = speed of light =
Now put all the given values in the above formula, we get:
Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be,
Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
