Answer:
f = 0.6× 10¹⁶ Hz
Explanation:
Given data:
Wavelength of radiation = 5.00 × 10⁻⁸ m
Frequency of radiation = ?
Solution:
Formula:
Speed of light = wavelength × frequency
speed of light = 3 × 10⁸m/s
Now we will put he values in formula.
3 × 10⁸m/s = 5.00 × 10⁻⁸ m × f
f = 3 × 10⁸m/s / 5.00 × 10⁻⁸ m
f = 0.6× 10¹⁶ s⁻¹
s⁻¹ = Hz
f = 0.6× 10¹⁶ Hz
Metallic bonds are found in metals like zinc.
Answer:
Ok let's do this how are you❤️
Answer:
Mg
Explanation:
The standard reduction potentials are
<u>E°/V
</u>
Au³⁺(aq ) + 3e⁻ ⟶ Au(s); 1.42
Hg²⁺(aq) + 2e⁻ ⟶ Hg(l); 0.85
Ag⁺(aq) + e⁻ ⟶ Ag(s); 0.80
Cu²⁺(aq) + 2e⁻ ⟶ Cu(s); 0.34
Mg2+(aq) + 2e- ⟶ Mg(s); -2.38
The more negative the standard reduction potential, the stronger the metal is as a reducing agent.
Mg is the only metal with a standard reduction potential lower than that of Cu, so
Only Mg will react spontaneously with Cu²⁺.
Answer:
Please find the structure attached as an image
Explanation:
Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.
- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.
- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).
N.B: In the structure attached below, the counting is from the left to right (→).