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maxonik [38]
3 years ago
15

Help me out real quick points and I ain’t no story teller

Chemistry
1 answer:
Brut [27]3 years ago
3 0

Answer:

can't see sorry

Explanation:

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A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm
Vsevolod [243]

 The  total pressure  = 1.402 atm


<u><em>calculation</em></u>

Total  pressure = partial  pressure  of gas A + partial pressure of gas B +  partial pressure  of third gas

partial  pressure  of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm


partial pressure for third gas is calculated using ideal  gas equation

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p(pressure)=? atm

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R(gas constant)=0.0821 L.atm/mol.k

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make  p the subject of the formula by  diving both side by V

p =nRT/v


p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm



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6 0
3 years ago
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