Answer with Explanation:
We are given that
Fundamental frequency,f=88.4 Hz
Speed of sound,v=343 m/s
We have to find the first three overtones.
Tube is closed
The overtone of closed pipe is equal to odd number of fundamental frequency.
Therefore, the overtone of tuba

Where n=3,5,7,..
Substitute n=3

For second overtone

For third overtone

Answer:
if you need to get the work=force×displacement or if you need the velocity=displacement÷time taken
Explanation:
Let us assume that forces acting at point B are as follows.

= 0 ...... (1)
= 0
= 0 .......... (2)
Hence, formula for allowable normal stress of cable is as follows.

T = 
= 3925 kip
From equation (1),
= -3925
= -3925
= 12877.29 kip
From equation (2), -12877.29 (Cos 60) + W = 0
= 0
W = 6438.64 kip
Thus, we can conclude that greatest weight of the crate is 6438.64 kip.