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bonufazy [111]
4 years ago
8

Which test was conducted on the skin found under the victim’s nails

Physics
2 answers:
labwork [276]4 years ago
8 0

Answer:

DNA testing

Explanation:

Under the field of forensic science DNA testing or DNA evidence is considered as the most reliable source of getting accurate result. Decades of rigorous scientific study has made the DNA a golden strand of forensic science.

For example, this test can find out the presence of person at the crime scene, even a small sample of semen, blood, hair or skin can give out more information than any other test.

DENIUS [597]4 years ago
5 0

. Underclothes; Bedding; Dirty laundry; Fingernail scrapings; Cups/bottles ... A cigarette butt found at a crime scene may contain valuable DNA material in the dried ... DNA evidence from both the victim's blood and the perpetrator's skin cells may ... DNA testing must be conducted in a laboratory with dedicated facilities and ...

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A book weighing 1.2 kg stands on the table. We place our hand on the book with a force of 15.3 N. The reaction force of the tabl
babunello [35]

Answer:

27 N

Explanation:

It will be the force of the book  1.2 kg * 9.81 m/s^2   PLUS the force of your hand  15.3 N    ..... it will be in the OPPOSITE direction

1.2 * 9.81 + 15.3 = ~27.1 N

8 0
2 years ago
(a) What is the acceleration due to gravity on the surface of the Moon?
wolverine [178]
<h2>a)  Acceleration due to gravity on the surface of the Moon is 1.64 m/s²</h2><h2>b) Acceleration due to gravity on the surface of the Mars is 3.75 m/s²</h2>

Explanation:

a) Acceleration due to gravity

                  g=\frac{GM}{r^2}

         G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

  Mass of moon, M = 7.35 × 10²² kg

  Radius of moon, r = 1.73 × 10⁶ m

  Substituting

                  g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.73\times 10^{6})^2}=1.64m/s^2

Acceleration due to gravity on the surface of the Moon is 1.64 m/s²

b) Acceleration due to gravity

                  g=\frac{GM}{r^2}

         G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²

  Mass of Mars, M = 6.418 × 10²³ kg

  Radius of Mars, r = 3.38 × 10⁶ m

  Substituting

                  g=\frac{6.67\times 10^{-11}\times 6.418\times 10^{23}}{(3.38\times 10^{6})^2}=3.75m/s^2

Acceleration due to gravity on the surface of the Mars is 3.75 m/s²

7 0
3 years ago
For safety reasons, _________ continue to operate when the light switch is moved to the headlight position.
Pavlova-9 [17]

Answer:park lights and license plate illumination lamps

Explanation:

3 0
3 years ago
A driver speeds along a curved road and sees a fallen tree on the road. He applies the brakes but is unable to stop in time. Whe
Lelu [443]
It's -6 meters/seconds.
7 0
3 years ago
Read 2 more answers
1. How long would the car in Sample Problem C take to come to a stop from its initial velocity of 20.0 m/s to the west? How far
Brilliant_brown [7]

The time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

<h3>What is the distance?</h3>

The length of the path traveled by the body is known as the distance covered by the body.

Distance is a 1-dimensional phenomenon. its unit is a meter(m). The distance can be found by the product of velocity and time.

The given data in the problem will be

u is the initial velocity =20m/sec

t is the time =?

d is the distance =?

From the Newtons second law;

\rm  F \triangle t = \triangle P \\\\ \triangle t = \frac{\triangle P }{F} \\\\ \triangle t = \frac{m(v_f-v_i)}{F} \\\\ \ \triangle t = \frac{2240 (0-20))}{8410} \\\\ \triangle t = 5.3 \ sec \\\

The distance travelled before the car stop is,

\rm \triangle t = \frac{1}{2} (v_f+v_i)\traingle t \\\\ \traingle x = \frac{1}{2} (-20+0)5.3 \\\\\ \triangle x= -53.3 m \ west

Hence,the time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

To learn more about the distance, refer to the link;

brainly.com/question/989117

#SPJ1

6 0
2 years ago
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