The greater the change in velocity, or speed.
Answer:
The average velocity of Samuel’s entire trip is 1.16 m/s.
Explanation:
Given:
Distance covered at first checkpoint (d₁) = 925 m
Distance covered at second checkpoint (d₂) = 673 m
Time taken for reaching first checkpoint (t₁) = 10 min = 10 × 60 = 600 s [∵1 min = 60 s]
Time taken for reaching second checkpoint (t₂) = 13 min = 13 × 60 = 780 s
Now, the average velocity of Samuel's entire trip is given by the formula:
Total distance traveled is equal to the sum of the distances traveled at first and second checkpoints. So,
Total distance covered =
Total time taken =
Therefore, the average velocity is given as:
Hence, the average velocity of Samuel’s entire trip is 1.16 m/s.
Work done (energy) = force * distance
So: distance = work done / force
= 2.7 / 4.5
= 0.6m
Answer:
4.5 m/s
Explanation:
The rock must barely clear the shelf below, this means that the horizontal distance covered must be
while the vertical distance covered must be
The rock is thrown horizontally with velocity , so we can rewrite the horizontal distance as
where t is the time of flight. Re-arranging the equation,
(1)
The vertical distance covered instead is
where we omit the term since the initial vertical velocity is zero. From this equation,
(2)
Equating (1) and (2), we can solve the equation to find :