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Sav [38]
4 years ago
11

If the man on the left pulls on the object with a force of 500 N and the man on the right pulls on the object with a force of 75

0 N, what is the net force exerted on the object?
A.
1250 N to the right
B.
1250 N to the left
C.
250 N to the right
D.
250 N to the left
Physics
1 answer:
Igoryamba4 years ago
3 0
Force is a vector quantity
so pulling from opposite side will be negative
so
750+(-500)= 250N
C is the right answer
becauseause the man on the right applies greater force.
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An ant climbs at a steady speed up the side of its
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<u>Given the following data:</u>

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<h3>What is a free-body diagram?</h3>

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8 0
2 years ago
PLEASE HELP I can't figure it out
PSYCHO15rus [73]
D. I know that like the back of my hand
4 0
4 years ago
Calculate the work done (in J) by a 90.0 kg man who pushes a crate 4.25 m up along a ramp that makes an angle of 20.0° with the
Mrrafil [7]

Answer:

W = 3.4x0³ J.

Explanation:

The work done by the man is given by the following equation:

W = F_{t}\cdot d     (1)

<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>  

We need to find first the total force Ft, which is:

Ft = Fm + W

<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°.  </em>

F_{t} = Fm + W = 500 N + 90.0 kg*9.81 m/s^{2} * sin(20.0) = 802.0 N

Hence, the work is:

W = 802.0 N \cdot 4.25 m = 3.4 \cdot 10 ^{3} J  

Therefore, the work done by the man is 3.4x10³ J.  

I hope it helps you!      

8 0
3 years ago
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photoshop1234 [79]
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Hope this helps! :D
7 0
3 years ago
Read 2 more answers
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