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monitta
2 years ago
9

If the same strength force were exerted on both wheelchairs, which chair would go faster?

Engineering
1 answer:
kaheart [24]2 years ago
6 0

Answer:

Hello!!

If the same strength force is exerted on two objects, but the objects have the different masses, the object with less mass will have a greater change in velocity. ... Forces affect motion because they can change an objects motion.

Explanation:

I hope it's help you ✌️✌️

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Carbon resistors often come as a brown cylinder with colored bands. These colored bands can be read to determine the manufacture
alexandr1967 [171]

Answer:

a) 4.7 kΩ, +/- 5%

b) 2.0 MΩ, +/- 20%

Explanation:

a) If the resistor has the following combination of color bands:

1) Yellow = 1st digit = 4

2) Violet = 2nd digit = 7

3) Red = multiplier = 10e2

4) Gold = tolerance = +/- 5%

this means that the resistor has 4700 Ω (or 4.7 kΩ), with 5% tolerance.

b) Repeating the process for the following combination of color bands:

1)  Red = 1st digit = 2

2) Black = 2nd digit = 0

3) Green = multiplier = 10e5

4) Nothing = tolerance = +/- 20%

This combination represents to a resistor of 2*10⁶ Ω (or 2.0 MΩ), with +/- 20% tolerance.

7 0
3 years ago
Technician A says that the definition of torque is how far the crankshaft twists in degrees.Technician B says that torque can re
leonid [27]
Technician B is correct because torque is a force of an object.
6 0
1 year ago
What material resources and intellectual resources were used in self driving cars?
fomenos

Answer: material resources: cameras, light detection and ranging systems, radar, sensors, advanced GPS, and millions of miles of training data, and more

I don't know about the intellectual resources sorry

5 0
3 years ago
How much to build a barber clipper?
goldenfox [79]
Like the price to manufacture?
8 0
3 years ago
For a bronze alloy, the stress at which plastic deformation begins is 266 MPa and the modulus of elasticity is105 GPa.
pentagon [3]

Answer:

88750 N

Explanation:

given data:

plastic deformation σy=266 MPa=266*10^6 N/m^2

cross-sectional area Ao=333 mm^2=333*10^-6 m^2

solution:

To determine the maximum load that can be applied without

plastic deformation (Fy).

Fy=σy*Ao

   =88750 N

7 0
3 years ago
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