Answer:
Explanation:
Given
velocity at A is
For
velocity is increasing at
Tangential acceleration is given by
at
thus
Velocity in terms of Displacement is given by
When car has traveled th of distance i.e.
on solving we get
Thus velocity at
(b)Acceleration when car has traveled three-fourth the way of track
normal acceleration
Tangential acceleration
Net acceleration
Answer:
I'm going to make a list of everything you need to consider for the supervision and design of the bridge.
1. the materials with which you are going to build it.
2. the length of the bridge.
3. The dynamic and static load to which the bridge will be subjected.
4. How corrosive is the environment where it will be built.
5.wind forces
6. The force due to possible earthquakes.
7. If it is going to be built in an environment where snow falls.
8. The bridge is unique,so the shape has a geometry that resists loads?.
9. bridge costs.
10. Personal and necessary machines.
11. how much the river grows
Answer:a
a) Vo/Vi = - 3.4
b) Vo/Vi = - 14.8
c) Vo/Vi = - 1000
Explanation:
a)
R1 = 17kΩ
for ideal op-amp
Va≈Vb=0 so Va=0
(Va - Vi)/5kΩ + (Va -Vo)/17kΩ = 0
sin we know Va≈Vb=0
so
-Vi/5kΩ + -Vo/17kΩ = 0
Vo/Vi = - 17k/5k
Vo/Vi = -3.4
║Vo/Vi ║ = 3.4 ( negative sign phase inversion)
b)
R2 = 74kΩ
for ideal op-amp
Va≈Vb=0 so Va=0
so
(Va-Vi)/5kΩ + (Va-Vo)74kΩ = 0
-Vi/5kΩ + -Vo/74kΩ = 0
Vo/Vi = - 74kΩ/5kΩ
Vo/Vi = - 14.8
║Vo/Vi ║ = 14.8 ( negative sign phase inversion)
c)
Also for ideal op-amp
Va≈Vb=0 so Va=0
Now for position 3 we apply nodal analysis we got at position 1
(Va - Vi)/5kΩ + (Va - Vo)/5000kΩ = 0 ( 5MΩ = 5000kΩ )
so
-Vi/5kΩ + -Vo/5000kΩ = 0
Vo/Vi = - 5000kΩ/5kΩ
Vo/Vi = - 1000
║Vo/Vi ║ = 1000 ( negative sign phase inversion)
Answer:
Hook's law holds good up to. A elastic limit. B. plastic limit. C.yield point. D.Breaking point
Answer:
Im guessing this is for CEA for PLTW, if so look up the exact assignment number and look at online examples of the exact same assignment.
Explanation: