2 years ago

WHO EVER COMMENTS FIRST GETS BRAINLIEST LOL

Engineering

2 answers:

Pachacha [2.7K]2 years ago

7 0

Answer:

g the djnsbsgsuks bbvv

galben [10]2 years ago

5 0

Answer:i want to be brainliest

Explanation: im new here

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Multiple Choice

ra1l [238]

I need more details to your question

4 0

1 year ago

Read 2 more answers

A motor is mounted on a platform that is observed to vibrate excessively at an operating speed of 6000 rpm producing a 250-N for

vichka [17]

Answer:

The amplitude of the absorbed mass can be found

for ka:

$X_{a} =0.002m=\frac{F_{0} }{K_{a} } =\frac{250}{K_{a} } =125000N/m$

now

$w^2=\frac{K_{a} }{m_{a} } \\m_{a} =\frac{K_{a} }{w^2} =\frac{125000}{[6000*2\pi /60]^2} =0.317kg$

4 0

2 years ago

Ammonia vapor becomes irritating to the<br> nose and throat at a concentration of<br> ___ppm

mr_godi [17]

Answer: Even low airborne concentrations (100 ppm) of ammonia may produce rapid eye and nose irritation.

8 0

2 years ago

A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fract

Hitman42 [59]

Answer:

radius = 9.1 × $10^{-3}$ m

Explanation:

given data

applied load = 5560 N

flexural strength = 105 MPa

separation between the support = 45 mm

solution

we apply here minimum radius formula that is

radius = $\sqrt[3]{\frac{FL}{\sigma \pi}}$ .................1

here F is applied load and is length

put here value and we get

radius = $\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}$

solve it we get

radius = 9.1 × $10^{-3}$ m

8 0

2 years ago

Can you answer what is attached.

kirill [66]

29.4 bro I hope that helps

3 0

2 years ago