Answer:
The resistance of the coil is 4 Ω.
Explanation:
The resistance (R) of the coil can be calculated using the following equation:
Where:
ρ: is the resistivity of copper = 0.02x10⁻⁶ Ωm
L: is the length of the coil
A: is the cross-sectional area = 0.8 mm² = 8x10⁻⁷ m²
The length of the coil is given by:
Now, the resistance is:
Therefore, the resistance of the coil is 4 Ω.
I hope it helps you!
Answer:
The process is not possible.
Explanation:
We know for ideal condition, the work done for isothermal process is
=
and for ideal gas, we know PV = mRT
Therefore, = mRT
= mRT
= 0.287 x 400
= -126.12 kJ/kg (negative sign indicates that the process is compressive, so work input to the compressor is 126.12 kJ/kg )
Now we know for adiabatic compression process
P = C
We know
= 556 K
For adiabatic work done, =
=
=
= -99.49 kJ/kg (negative sign indicates that the process is compressive, so work input to the compressor is 99.49 kJ/kg )
We know that in isothermal process, work input to the compressor is minimum. But in the above adiabatic polytropic process, work input to the compressor is less than the work done in the isothermal process.
Thus the process is not possible.
Answer:
see explaination
Explanation:
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