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Natali5045456 [20]
3 years ago
9

How do I turn 2 s into one in the products

Chemistry
1 answer:
-BARSIC- [3]3 years ago
5 0
Make the equation equal on each side.

With number 1 it says the left side of the arrow has 1 Sn, 2 S, and 2 O.

The right has 1 Sn, 4 O, and 1 S.

So you have to balance the equation by putting numbers in front of the compounds.

SnS2 + O2 = SnO2 + SO2

SnS2 + 3 O2 = SnO2 + 2 SO2

Now there is 1 Sn, 2 S. and 6 O on each side. The large number in front of the compounds essentially multiplies it by that the subscript of that number. So with O2 it says there are 2 Oxygens. So they come in pairs. If you get 3 pairs of Oxygens there will be 6.

The same process goes with the rest of them too. Sometimes it takes a few guesses. Just figure them out like an algebra problem. Put the equal sign between them like I did. It maked it easier for me.
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You observe an exothermic gaseous reaction that is not spontaneous in forward direction at 1 atm and 298K. Which of the followin
m_a_m_a [10]

Answer: option (a) is the correct answer

Explanation:

The complete questions says;

You observe an exothermic gaseous reaction that is not spontaneous in forward direction at 1 atm and 298K. Which of the following statements about this reaction is true? a. This reaction will become spontaneous in forward direction at some temperature below 298K. b. This reaction will be spontaneous in forward direction at a higher pressure at 298K. c. This reaction will become spontaneous in forward direction at some temperature above 298K. d. This reaction is never spontaneous. e. The reverse reaction is always spontaneous.

The Answer:

(a). This reaction will become spontaneous in forward direction at some temperature below 298K

Explanation: First of all, we can acknowledge that the reaction seen here is an exothermic one, i.e energy is released in the process outwardly and as a result temperature is reduced during this process of energy loss.

Having understood that scenario, say we reduce it's temperature by ourself than forward reaction favors and after reaching at particular temperature, therefore we can confirm this to be a spontaneous reaction.

Let us use this to confirm what we have been saying.

Given;

ΔG = ΔH - TΔS

here ΔH is negative

it is non spontaneous, which means ΔG is positive so we continuously decraeses it's temperature than at a particular temperature.

The Entropy change becomes positive and reaction becomes spontaneous and ΔG become negative.

cheers i hope this helped !!

8 0
3 years ago
What are the concentrations of Cu2+, NH3, and Cu(NH3)42+ at equilibrium when 18.8 g of Cu(NO3)2 is added to 1.0 L of a 0.800 M s
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Answer:

Explanation:

Cu(NO₃)₂ + 4NH₃ = Cu(NH₃)₄²⁺  + 2 NO₃⁻

187.5 gm      4M           1 M

187.5 gm reacts with 4 M ammonia

18.8 g     reacts with  .4 M ammonia

ammonia remaining left after reaction

= .8 M - .4 M = .4 M .

187.5 gm reacts with 4 M ammonia   to form 1 M Cu(NH₃)₄²⁺

18.8 g reacts with .4 M ammonia  to form 0.1 M Cu(NH₃)₄²⁺  

At equilibrium , the concentration of Cu²⁺ will be zero .

concentration of ammonia will be .4 M

concentration of  Cu(NH₃)₄²⁺ formed will be 0.1 M

3 0
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pantera1 [17]

Answer:

it is a because blood is pumped but heart so the answer is A

4 0
2 years ago
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