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2 years ago

What happens in your cells with cellular respiration?

Chemistry

2 answers:

marshall27 [118]2 years ago

7 0

Answer:

Hello There!!

Explanation:

Cellular respiration releases stored energy in glucose molecules and converts it into a form of energy that are used by cells.Energy released during the reaction is captured by the energy-carrying molecule ATP a chemical which the cell uses for energy.

hope this helps,have a great day!!

~Pinky~

attashe74 [19]2 years ago

6 0

Cellular respiration releases stored energy and glucose molecules and converts it into a form of energy that can be used by cells

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When one of the atoms involved in a covalent bond has a much higher electronegativity than the other atom, what type of bond res

ICE Princess25 [194]

If electronegativity difference between atoms is much higher then they form ionic bond.

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5 0

3 years ago

A standard solution of FeSCN2+ is prepared by combining 9.0 mL of 0.20 M Fe(NO3)3 with 1.0 mL of 0.0020 M KSCN . The standard so

Xelga [282]

Answer : The equilibrium concentration of $SCN^-$ in the trial solution is $4.58\times 10^{-8}M$

Explanation :

First we have to calculate the initial moles of $Fe^{3+}$ and $SCN^-$ .

$\text{Moles of }Fe^{3+}=\text{Concentration of }Fe^{3+}\times \text{Volume of solution}$

$\text{Moles of }Fe^{3+}=0.20M\times 9.0mL=1.8mmol$

and,

$\text{Moles of }SCN^-=\text{Concentration of }SCN^-\times \text{Volume of solution}$

$\text{Moles of }SCN^-=0.0020M\times 1.0mL=0.0020mmol$

The given balanced chemical reaction is,

$Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons FeSCN^{2+}(aq)$

Since 1 mole of $Fe^{3+}$ reacts with 1 mole of $SCN^-$ to give 1 mole of $FeSCN^{2+}$

The limiting reagent is, $SCN^-$

So, the number of moles of $FeSCN^{2+}$ = 0.0020 mmole

Now we have to calculate the concentration of $FeSCN^{2+}$ .

$\text{Concentration of }FeSCN^{2+}=\frac{0.0020mmol}{9.0mL+1.0mL}=0.00020M$

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution

l = path length

$\epsilon$ = molar absorptivity coefficient

$\epsilon$ and l are same for stock solution and dilute solution. So,

$\epsilon l=\frac{A}{C}=\frac{0.480}{0.00020M}=2400M^{-1}$

For trial solution:

The equilibrium concentration of $SCN^-$ is,

$[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]$

$[SCN^-]_{initial}$ = 0.00050 M

Now calculate the $[FeSCN^{2+}]$ .

$C=\frac{A}{\epsilon l}=\frac{0.220}{2400M^{-1}}=9.17\times 10^{-5}M$

Now calculate the concentration of $SCN^-$ .

$[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]$

$[SCN^-]_{eqm}=(0.00050M)-(9.17\times 10^{-5}M)$

$[SCN^-]_{eqm}=4.58\times 10^{-8}M$

Therefore, the equilibrium concentration of $SCN^-$ in the trial solution is $4.58\times 10^{-8}M$

5 0

3 years ago

X2o3 express you answer as a whole number

kobusy [5.1K]

<span>2.40 - 1.68 =0.72 g of oxigen
moles = 0.72/16 g/mol=0.045

moles x = 1.68/ 55.9=0.03

0.03/0.03 = 1 = x
0.045 / 0.03 = 1.5 = O

to get whole numbers multiply by 2

x2O3

X2O3 +3 CO = 2 X + 3 CO2</span>

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3 years ago

What dangerous element does Feista Wear contain

strojnjashka [21]

uranium oxide

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3 0

2 years ago

Read 2 more answers

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Nuetrik [128]

Answer: