Answer : The value of work done for the system is 1144.69 J
Explanation :
First we have to calculate the moles of 

Molar mass of
= 65.01 g/mole

Now we have to calculate the moles of nitrogen gas.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 2 mole of
react to give 3 mole of 
So, 0.311 moles of
react to give
moles of 
Now we have to calculate the volume of nitrogen gas.
Using ideal gas equation:

where,
P = Pressure of
gas = 1.00 atm
V = Volume of
gas = ?
n = number of moles
= 0.466 mole
R = Gas constant = 
T = Temperature of
gas = 
Putting values in above equation, we get:


As initially no nitrogen was present. So,
Volume expanded = Volume of nitrogen evolved
Thus,
Expansion work = Pressure × Volume
Expansion work = 1.00 atm × 11.3 L
Expansion work = 11.3 L.atm
Conversion used : (1 L.atm = 101.3 J)
Expansion work = 11.3 × 101.3 = 1144.69 J
Therefore, the value of work done for the system is 1144.69 J