First get rid of the exponent: 6x + 3 = 243. then subtract 3 from both sides: 6x = 240. lastly divide both side by 6: x = 40. be sure to check your work by plugging it back in.
P(P|K) = 82.6%.
P(P|K) = P(K and P)/P(K) = 1.9%/2.3% = 0.019/0.023 = 0.8261 = 82.6%
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
Answer:
6x+y=-8 because it will be y=-6x-8 having same slope with the line given