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SOVA2 [1]
2 years ago
13

Help please 10 pts and quick! can someone write me a short response

Physics
1 answer:
zmey [24]2 years ago
6 0

Answer:

Explanation:

Pecan 1 and 4 seem the best answer

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What is the distance traveled per unit time called?
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The distance traveled per unit time is called speed.
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3 years ago
The total pressure for a fluid is a. the sum of the hydrostatic and static pressures. b. the sum of the hydrostatic and dynamic
m_a_m_a [10]

<h2>The option a is most appropriate </h2>

Explanation:

The total pressure due to liquid column at any place is the sum of

( i ) pressure due to liquid column called hydrostatic pressure

( ii ) the pressure due to air column above the liquid column , which is called the static pressure

Thus total pressure is the sum of hydrostatic and static pressure .

Thus the option a is most appropriate

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3 years ago
Which do you think would stronger the gravitational interaction between an apple and earth or the gravitational interaction betw
Anna11 [10]

apple, earth. earth more massive than moon. astronauts showed this - armstrong etc

8 0
3 years ago
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How to find a scale for a graph
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8 0
3 years ago
Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of
STatiana [176]

Answer:

2.27\cdot 10^{49}

Explanation:

The gravitational force between the proton and the electron is given by

F_G=G\frac{m_p m_e}{r^2}

where

G is the gravitational constant

m_p is the proton mass

m_e is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N

The electrical force between the proton and the electron is given by

F_E=k\frac{q_p q_e}{r^2}

where

k is the Coulomb constant

q_p = q_e = q is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N

So, the ratio of the electrical force to the gravitational force is

\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}

So, we see that the electrical force is much larger than the gravitational force.

5 0
3 years ago
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