Help please 10 pts and quick! can someone write me a short response

A truck moves 70 m east, then moves 120 m west, andfinally

SOVA2 [1]

Answer:

40m (40m east)

Explanation:

The fist move is 70m east, and east is the positive direction so the truck initially is at +70m.

The second move is 120m to the west, since east is the positive direction, west must be the negative direction, this means the truck now is at:

$+70m -120m = -50m$

The third move is 90m to the east, again, this is the positive direction, so the new position is:

$-50m + 90m = +40m.$

The truck is at + 40m, so it ended up 40m away from its initial position and this is the resultant dispacement.

7 0

2 years ago

A steel tape (a=1.300 E-5 per Celsius degrees) measures 200.0 m at 15.00 degrees celsius. It’s length at 55.00 degrees celsius i

Verizon [17]

Answer:

200.1 m is the answer

8 0

2 years ago

__________ force is a fictitious force that some people believe causes you to feel as if you are being pushed outward from the c

jok3333 [9.3K]

The complete sentence is:
Centrifugal force is a fictitious force that some people believe causes you to feel as if you are being pushed outward from the center of a circle while traveling in uniform circular motion.

In fact, centrifugal force is an inertial force: it is not a real force, but it is due to the fact that the reference frame is rotating. The real force in a uniform circular motion is the centripetal force, which pushes towards the centre of the circle, and keeps the object in circular motion.

5 0

3 years ago

Read 2 more answers

A person is using a rope to lower a 5.0-n bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the forc

OLga [1]

Answer:

5 N

Explanation:

The bucket is moving at a constant speed of 2m/s Therefore F=ma is 0 N for this to be correct the magnitude of the force exerted by the rope must be equal to the weight of the bucket which is 5 N

7 0

2 years ago

Read 2 more answers

Two workers pull horizontally on a heavy box. but one pulls twice as hard as the other. The larger pull is directed at 21.0° wes

pantera1 [17]

Answer:

The magnitude of F1 is

$|F1|=358.74 \ N$

The magnitude of F2 is

$|F2|=179.37\ N$

And the direction of F2 is

$\alpha = 44.214^o$

Explanation:

Net Force

Forces are represented as vectors since they have magnitude and direction. The diagram of forces is shown in the figure below.

The larger pull F1 is directed 21° west of north and is represented with the blue arrow. The other pull F2 is directed to an unspecified direction (red arrow). Since the resultant Ft (black arrow) is pointed North, the second force must be in the first quadrant. We must find out the magnitude and angle of this force.

Following the diagram, the sum of the vector components in the x-axis of F1 and F2 must be zero:

$\displaystyle -2F\ sin21^o+F\ cos\alpha =0$