Empirical formula is the simplest ratio of whole numbers of components in a compound
calculating for 100 g of compound
N O
mass 46.7 g 53.3 g
number of moles 46.7 g / 14 g/mol 53.3 g / 16 g/mol
= 3.33 = 3.33
divide by the least number of moles
3.33/ 3.33 = 1.00 3.33/3.33 = 0
number of atoms
N - 1
O - 1
therefore empirical formula is NO
Neutrons the way this question is setup the atom would not be able to be neutral
Answer:2 Fr because is has the lowest electronegativity 0.79
I would say Na. Oxygen has 2 valence electrons and when reacting with other molecules, the ones with the fullest or emptiest shells will react the least. Both H2 and Na are in the Alkali Metals in the first row, but since H2 has 2 molecules, it would use more oxygen than Ana
