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Arturiano [62]
2 years ago
14

If the temperature and amount of gas stays constant, what will happen to the pressure of a gas if the volume of the container de

creases?
Chemistry
1 answer:
devlian [24]2 years ago
4 0
If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase. However, if you were to maintain a constant volume while decreasing pressure, the temperature would also have to decrease.
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Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L
const2013 [10]

Answer:

The answer is 1.15m.

Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of H2SO4 and the mass of the solvent, which I presume is water.

We can find the number of H2SO4 moles by using its molarity

C=nV→nH2SO4=C⋅VH2SO4=6.00molesL⋅48.0⋅10−3L=0.288

Since water has a density of 1.00kgL, the mass of solvent is

m=ρ⋅Vwater=1.00kgL⋅0.250L=0.250 kg

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4 0
3 years ago
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Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?
Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms    Electronegativity          Bond        Electronegativity difference

Cl                          3.0                       Cl-F                      1.0

Br                          2.8                       Br-Cl                     0.2

F                            4.0                       Cl-Cl                      0

H                            2.1                       H-C                       0.4

C                            2.5                       H-N                       0.9

N                             3.0                      H-O                       1.4

O                             3.5                      Br-F                       1.2

I                               2.7                      I-F                         1.3

Si                             1.9                      Cl-F                       1.0  

P                              2.2                      Si-Cl                      1.1

                                                          Si-P                        0.3

                                                          Si-C                        0.6

                                                           Si-F                        2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

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