Answer: 31 & 42
<u>Step-by-step explanation:</u>
1st #: x
2nd #: x + 11
1st# + 2nd# = sum
x + x + 11 = 73
2x + 11 = 73
2x = 62
x = 31
2nd #: x + 11 = 31 + 11 = 42
Answer:
(f o g)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x²-5
(f o g)(4)=?
(f o g)(4) = f(g(4))
Calculating g(4):
x=4→g(4)=4²-5
g(4)=16-5
g(4)=11
Replacing g(4)=11
(f o g)(4) = f(g(4))
(f o g)(4) = f(11)
Calculating f(11)
x=11→f(11)=4(11)+1
f(11)=44+1
f(11)=45
Replacing f(11)=45:
(f o g)(4) = f(11)
(f o g)(4) = 45
Answer:
<u>Kevin's height increased 19.05%</u>
Step-by-step explanation:
Height of Kevin at the beginning of sixth grade = 4’10”
Height of Kevin at the end of ninth grade = 5’9”
What was the percentage of increase in Kevin height?
For answering this question, we should convert Kevin's heights to decimal number, this way:
1 feet = 12 inches
4’10” = 4 10/12 = 4.83
5’9” = 5 9/12 = 5.75
Now, let's use the Direct Rule of Three:
Height Percentage
4.83 100
5.75 x
***********************************
4.83x = 5.75 * 100
4.83x = 575
x = 575/4.83
x = 119.05
119.05 - 100 = 19.05
<u>Kevin's height increased 19.05%</u>
