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Vikki [24]
3 years ago
12

Which two statements are true of electromagnetic waves?

Physics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

AD

Explanation:

electromagnetic waves do not need a medium to travel, examples are ultraviolet radiation and infrared radiation.

Angelina_Jolie [31]3 years ago
6 0

Answer:

A and D

Explanation:

Just did it

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How much pressure is created by a circular piston that is 0.24 meter in diameter
Vedmedyk [2.9K]

Answer:

4000 N/m²

Explanation:

Area = πr²

Area = π x 0.12² (diameter/2)

Area = 0.05 m²

Pressure = force/area

Pressure = 200/0.05

Pressure = 4000 N/m²

Hope this helps!

8 0
3 years ago
Which of the following is WRONG?
iren2701 [21]
It’s D the time period within pendulums are constant, distance is always measured with kilometers within cities and basic unit is always seconds.
3 0
3 years ago
Read 2 more answers
You weigh 716 newtons on Earth. You
Otrada [13]

Answer:

537 N

Explanation:

The force due to gravity of a planet is:

F = GMm / r²

where G is the universal gravitational constant

M is the mass of the planet

m is the mass of the object

and r is the distance between the object and the center of the planet

On Earth, you weigh 716 N, so:

716 N = GMm / r²

On planet X:

F = G (3M) m / (2r)²

F = 3/4 GMm / r²

F = 3/4 (716 N)

F = 537 N

8 0
4 years ago
Which is a transverse wave that requires a medium to move?
Ronch [10]
<span>the transverse wve that requires a medium to move is : sound waves in order to travel, sound waves need to jumped on between one particle to another, no matter it's liquid, solid , and gases. Which explains why you wont hear a thing in outer space, simply because the sound waves got no particle to jumped into</span>
4 0
4 years ago
The magnetic field perpendicular to a single 13.2-cm diameter circular loop of copper wire decreases uniformly from 0.670 T to z
shusha [124]

Answer:

5.23 C

Explanation:

The current in the wire is given by I = ε/R where ε = induced emf in the wire and R = resistance of wire.

Now, ε = -ΔΦ/Δt where ΔΦ = change in magnetic flux = AΔB and A = area of loop and ΔB = change in magnetic field intensity = B₂ - B₁

B₁ = 0.670 T and B₂ = 0 T

ΔB = B₂ - B₁ = 0 - 0.670 T = - 0.670 T

A = πD²/4 where D = diameter of circular loop = 13.2 cm = 0.132 m

A = π(0.132 m)²/4 = 0.01368 m² = `1.368 × 10⁻² m²

ε = -ΔΦ/Δt = -AΔB/Δt = -1.368 × 10⁻² m² × (-0.670 T)/Δt= 0.9166 × 10⁻² Tm²/Δt

Now, the resistance R of the circular wire R = ρl/A' where ρ = resistivity of copper wire =  1.68 x 10⁻⁸ Ω.m, l = length of wire = πD and A' = cross-sectional area of wire = πd²/4 where d = diameter of wire = 2.25 mm = 2.25 × 10⁻³ m

R = ρl/A' = 1.68 x 10⁻⁸ Ω.m × π × 0.132 m÷π(2.25 × 10⁻³ m)²/4 = 0.88704/5.0625 = 0.1752 × 10⁻² Ω = 1.752 × 10⁻³ Ω

So, I = ε/R = 0.9166 × 10⁻² Tm²/Δt1.752 × 10⁻³ Ω  

IΔt = 0.9166 × 10⁻² Tm²/1.752 × 10⁻³ Ω = 0.5232 × 10 C

Since ΔQ = It = 5.232 C ≅ 5.23 C

So the charge is 5.23 C

6 0
3 years ago
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