Answer: the maximum heigth of the stadium at ist back wall is 151.32 ft
Explanation:
1. use the position (x) equation in parobolic movement to find the time (t)
565 ft = [frac{176 ft}{1 s\\}[/tex] * cos (35°) * t
t= 3.92 s
2. use the position (y) equation in parabolic movement to find de maximun heigth the ball reaches at 565 ft from the home plate.
y= [[frac{176 ft}{1 s\\}[/tex] * sen (35°) * 3.92 s] - 
y= 148.32 ft
3. finally add the 3 ft that exist between the home plate and the ball
148.32 ft + 3 ft = 151.32
<span>The car would have traveled exactly one-half of the circumference of the track, since it would have gone from one extreme point to its opposite extreme point. This would be equal to (3.5 / 2), or 1.75 km. The northernmost point would be 1.75km away from the southernmost point.</span>
Precisely around 1,800 miles below.
Answer:
Explanation:
1. We can find the temperature of each star using the Wien's Law. This law is given by:
![\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}](https://tex.z-dn.net/?f=%5Clambda_%7Bmax%7D%3D%5Cfrac%7Bb%7D%7BT%7D%3D%5Cfrac%7B2.9x10%5E%7B-3%7D%5BmK%5D%7D%7BT%5BK%5D%7D)
(1)
So, the temperature of the first and the second star will be:
Now the relation between the absolute luminosity and apparent brightness is given:
(2)
Where:
- L is the absolute luminosity
- l is the apparent brightness
- r is the distance from us in light years
Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂
If we use the equation (2) we have:
So the relative distance between both stars will be:
(3)
The Boltzmann Law says, 
(4)
- σ is the Boltzmann constant
- A is the area
- T is the temperature
- L is the absolute luminosity
Let's put (4) in (3) for each star.
As we know both stars have the same size we can canceled out the areas.
I hope it helps!
