All categories

2 years ago

A force of 30 N is applied to an object with a mass of 15 kg. What is the resulting acceleration?

Physics

2 answers:

svet-max [94.6K]2 years ago

5 0

Answer:

We know that Force = mass × acceleration

By substituting the values we get,

30 N = 15 kg × a (where a is acceleration)

Or we can write it as

15 kg × a = 30 N

Transposing 15 to RHS,

a = 30 ÷ 15 m/s²

Therefore, acceleration = 2 m/s²

pls give brainliest for the answer

Gnoma [55]2 years ago

4 0

Just remember when dealing with Newton II (where F=m*a), that F is the net (or resultant) force on the object. 30/15=2m/s

You might be interested in

PLEASE HELP. THIS IS DUE TODAY AT 11:59PM

OLga [1]

Answer:

ggn

Explanation:

4 0

3 years ago

What is the length of a string with a mass of 2.5 kg, with a

natulia [17]

B 0.4 m should be correct if not it is A

4 0

3 years ago

One observer stand on a train moving at a constant speed, and one observer stands at rest on the ground. The person on the train

ANTONII [103]

Answer:

b) Equal to c

Explanation:

According to relativity, the speed of light in free space is constant in all inertial reference frame.

3 0

3 years ago

The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). W

FromTheMoon [43]

Answer: $\alpha =30-4=26 rad/s^2$

Explanation:

Given

Position of a car is given by

$\theta =t^3-2t^2-4t+10$

and angular speed is $\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega$

angular acceleration is

$\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha$

$\alpha =6t-4$

at $t=5 s$

$\alpha =30-4=26 rad/s^2$

4 0

3 years ago

24 A uniform electric field of magnitude 1.1×104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the elect

Tatiana [17]

Answer:

$44,000 Nm^2/C$

Explanation:

The electric flux through a certain surface is given by (for a uniform field):

$\Phi = EA cos \theta$

where:

E is the magnitude of the electric field

A is the area of the surface

$\theta$ is the angle between the direction of the field and of the normal to the surface

In this problem, we have:

$E=1.1\cdot 10^4 N/C$ is the electric field

L = 2.0 m is the side of the sheet, so the area is

$A=L^2=(2.0)^2=4.0 m^2$

$\theta=0^{\circ}$ , since the electric field is perpendicular to the surface

Therefore, the electric flux is

$\Phi =(1.1\cdot 10^4)(4.0)(cos 0^{\circ})=44,000 Nm^2/C$

4 0

3 years ago