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notsponge [240]
3 years ago
8

A force of 30 N is applied to an object with a mass of 15 kg. What is the resulting acceleration?

Physics
2 answers:
svet-max [94.6K]3 years ago
5 0

Answer:

We know that Force = mass × acceleration

By substituting the values we get,

30 N = 15 kg × a (where a is acceleration)

Or we can write it as

15 kg × a = 30 N

Transposing 15 to RHS,

a = 30 ÷ 15 m/s²

Therefore, acceleration = 2 m/s²

pls give brainliest for the answer

Gnoma [55]3 years ago
4 0
Just remember when dealing with Newton II (where F=m*a), that F is the net (or resultant) force on the object. 30/15=2m/s
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A sailboat is traveling across the ocean with a speed of 4 m/s when large gusts of wind pick up that starts to accelerate the sa
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solution:

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8 0
4 years ago
The capacitance of the variable capacitor of a radio can be changed from 100 to 350 pF by turning the dial from 0° to 180°. With
tangare [24]

Answer:

0.7 mJ

Explanation:

<u>Identify the unknown:  </u>

The work required to turn the dial from 180° to 0°  

<u>List the Knowns:  </u>

Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F  

Voltage of the battery: V = 130 V  

<u>Set Up the Problem:</u>  

<em><u>Energy stored in a capacitor: </u></em>

U_c=1/2*V^2*C

      =1/2*Q^2/C

<em><u>When the dial is set at 180°:</u></em><em>  </em>

U_c=1/2*(130)^2*350*10^-12=10^-4

Q=√2*U_c*C=4*10^-7

<u><em>When the dial is set at 0°:</em></u>  

U_c=1/2*(4*10^-7)^2/100*10^-12

      =8*10^-4 J

<u><em>Solve the Problem:  </em></u>

ΔU_c=7*10^-4 J

        =0.7 mJ

note:

there maybe error in calculation but method is correct

4 0
3 years ago
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PSYCHO15rus [73]

Answer:

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Explanation:

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Answer:

Explanation:

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3 years ago
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