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SVETLANKA909090 [29]
3 years ago
7

Describe the full water cycle

Physics
1 answer:
sergey [27]3 years ago
5 0

The water cycle (hydro-logic cycle), explains the constant motion of water on, above and below the surface of the Earth. The mass of water on Earth stays equally constant over time, although the severe portion of the water goes into the major reservoirs of ice, fresh water, saline water and atmospheric water is variable depending on a wide range of climatic variables. The water moves from one reservoir to another, such as from river to ocean, or from the ocean to the atmosphere, by the physical processes of evaporation, condensation, precipitation, infiltration, surface runoff, and subsurface flow. In doing so, the water goes through different forms: liquid, solid (ice) and vapor.

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Label the producers and consumers, then label the different types of consumers.
sdas [7]
The base of the pyramid has the producers and everything else above the base falls under the consumers category i.e the locusts,frogs and the snake. The grass is the producer, the locust is a consumer, the frog is a special type of omnivore, termed the "life-history omnivore" since they eat both plants and animals but at different times in their lives. In this case they are just omnivores and lastly, the snake is a carnivore.
3 0
3 years ago
Convert 15 litre into cubic metre​
atroni [7]

Answer:

0.015m^3

Explanation:

1 m^3 = 1000 liters

x m^3 = 15 liters

Cross multiply

xm^3 x 1000 l = 15 l

Divide both sides by 1000

xm^3 x1000/1000 = 15/1000

xm^3 = 0.015m^3

Therefore 15 liter = 0.015m^3

5 0
3 years ago
The only force acting on a 2.5 kg canister that is moving in an xy plane has a magnitude of 3.0 N. The canister initially has a
Effectus [21]

Answer:44.58 J

Explanation:

mass of block \left ( m\right )=2.5 kg

Force magnitude=3 N

Initial velocity =2.3\hat{i} m/s

Final velocity=6.4\hat{j} m/s

Initial Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.5\times 2.3^2=6.612 J

Final Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.5\times 6.4^2=51.2 J

Work Done =Final -Initial Kinetic energy=51.2-6.612=44.58 J

4 0
3 years ago
A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8
puteri [66]
R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3

HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
                              =-20/8
                              =-2.5
7 0
3 years ago
Help for physics
12345 [234]

Answer:

A. 5 m/s

Explanation:

From the graph, for the first 2 seconds, the graph is a straight line meaning that the slope is a constant.

Average speed of an object is the rate of change of position. Here, the position of the object changes from 0 m to 10 m for a time interval of 2 seconds.

The change in position (\Delta x) and time interval (\Delta t) are given as:

\Delta x=10-0=10\ m\\\Delta t=2-0=2\ s

Therefore, the average speed (s_{avg}) is given as the ratio of the total change in position and the time interval for the change.

s_{avg}=\frac{\Delta x}{\Delta t}=\frac{10-0}{2-0}=\frac{10}{2}=5\ m/s

Hence, the average speed is 5 m/s.

8 0
3 years ago
Read 2 more answers
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