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Doss [256]
2 years ago
13

Find the energy in kJ for an x-ray photon with a frequency of 2.4 × 10^18 1/s.

Chemistry
1 answer:
Ilya [14]2 years ago
8 0

Answer:

15912 × 10∧-19 KJ

Explanation:

Given data;

frequency of photon = 2.4 × 10^18 1/s.

Planck's constant = 6.63 × 10∧-34 j.s

Energy = ?

Formula:

E = h × ν

E =  6.63 × 10∧-34 j.s ×  2.4 × 10^18 1/s

E= 15.912 × 10∧-16 j

now we will convert the joule into kilo joule,

E = 15.912 × 10∧-16 j /1000 = 15.912 × 10∧-19 KJ

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Answer:

  • <em>The net charge of the ionic compound calcium fluoride is </em><u><em>zero (0).</em></u>

<em>Explanation:</em>

<em>Ionic compounds,</em> such as covalent ones, have zero net charge; this is, they are neutral.

Substances with net positive charge are cations and substances with net negative charge are anions.

The charges in the <em>ionic compound calcium flouride</em> are distributed in this way:

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  • Then, the <em>net charge</em> is: 1 × (2+) + 2 × (1-) = +2 - 2 = 0.

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Explanation:

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Therefore, if one of the buffers that contributes to pH stability in human blood is carbonic acid, which is as a result of a combination of carbon dioxide and water in the blood stream. On getting to the lungs it is converted to water and subsequently released as waste. Maintaining this stability will definitely be to decrease the concentration of carbonic acid and increase that of water instead.  

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Answer:

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