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Doss [256]
3 years ago
13

Find the energy in kJ for an x-ray photon with a frequency of 2.4 × 10^18 1/s.

Chemistry
1 answer:
Ilya [14]3 years ago
8 0

Answer:

15912 × 10∧-19 KJ

Explanation:

Given data;

frequency of photon = 2.4 × 10^18 1/s.

Planck's constant = 6.63 × 10∧-34 j.s

Energy = ?

Formula:

E = h × ν

E =  6.63 × 10∧-34 j.s ×  2.4 × 10^18 1/s

E= 15.912 × 10∧-16 j

now we will convert the joule into kilo joule,

E = 15.912 × 10∧-16 j /1000 = 15.912 × 10∧-19 KJ

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Which is the correct measure of density?
Goryan [66]

\huge \sf༆ Answer ༄

Density is defined as Mass per unit volume of an object ~

And hence, the correct choice is ~ 1

\sf \dfrac{mass}{volume}

꧁  \:  \large \cal{TeeN \: ForeveR } \: ꧂

6 0
2 years ago
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Which statement about chemical reactions is not true?
igomit [66]

Answer:

1: New atoms are formed as products

Explanation:

matter (atoms) cannot be created or destroyed

unless you are God or Cinderella's fairy Godmother or something

7 0
3 years ago
In a 10-gram sample of carbon and a 10-gram sample of sulfur, how many more moles of carbon are there than sulfur?
8_murik_8 [283]
Your answer will be the second option

5 0
3 years ago
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Which of the following is a galvanic cell?
sladkih [1.3K]

C. Aluminum (Al) oxidized, zinc (Zn) reduced

<h3>Further explanation</h3>

Given

Metals that undergo oxidation and reduction

Required

A galvanic cell

Solution

The condition for voltaic cells is that they can react spontaneously, indicated by a positive cell potential.

\large {\boxed {\bold {E ^ ocell = E ^ ocatode -E ^ oanode}}}

or:  

E ° cell = E ° reduction-E ° oxidation  

For the reaction to occur spontaneously (so that it E cell is positive), the  E° anode must be less than the E°cathode

If we look at the voltaic series:

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>

The standard potential value(E°) from left to right in the voltaic series will be greater, so that the metal undergoing an oxidation reaction (acting as an anode) must be located to the left of the reduced metal (as a cathode)

<em />

From the available answer choices, oxidized Al (anode) and reduced Zn (cathode) are voltaic/galvanic cells.

7 0
3 years ago
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Answer these questions based on 234. 04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given.
nikdorinn [45]

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

<h3>How do we calculate atomic mass?</h3>

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

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Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

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Given mass of thorium-234 = 234.04360 amu

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Hence required value is 1.85864 amu.

To know more about Atomic mass (A), visit the below link:

brainly.com/question/801533

4 0
2 years ago
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