1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jek_recluse [69]
4 years ago
8

A charasteristic that helps a living thing survive

Chemistry
2 answers:
taurus [48]4 years ago
7 0
Ummmmmm adapt to there environment always have food around them
Fantom [35]4 years ago
3 0
Ability to adapt to their environment?? there isn't much context to the question /:
You might be interested in
How is copper sulphate different to copper sulphide in terms of the elments it contains
son4ous [18]

Answer:

An Element is a substance made up of only one type of atom as like gold, copper, oxygen, etc.

Copper sulphate with molecular formula (CuSO_4), the elements are copper, sulphur and oxygen. It is formed by combination of Cu^{2+} cation and SO_4^{2-} anion.

Copper sulphide with molecular formula (CuS), the elements are copper and sulphur. It is formed by combination of Cu^{2+} cation and S^{2-} anion.

6 0
3 years ago
At what point in the cooking process is food typically seared?
Wittaler [7]

Answer: when you look at the meat, and it looks beautiful like a crispy donut made by Gordan Ramsay

Explanation:

Hells Kitchen is kewl

5 0
3 years ago
Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
3 years ago
The reaction for the combustion of methane is shown below. If 28.70g of methane
antiseptic1488 [7]
Omg hard question but it’s also amazing imma think about that question
8 0
3 years ago
Help! The products of a chemical equation are CO2 and 2H20. Which set of atoms
elixir [45]

D. Ap3x just did it

---------

5 0
3 years ago
Read 2 more answers
Other questions:
  • We can change a gas to liquid by the temperature and the pressure. NextReset
    14·2 answers
  • Calculate the concentration in molality of calcium phosphate in a solution containing 250.0 grams of pure water when the freezin
    5·1 answer
  • Which is true of a mechanical wave? (Hurry up please, do quick)
    11·1 answer
  • write the chemical equation for the following reaction: the elements carbon and oxygen combine to yield the compound carbon diox
    5·2 answers
  • How much heat is needed to raise the temperature of 20.0g of H2O by 10.6oC?
    8·1 answer
  • Compare land cover and land use, explaining how they are related and describing one way that humans can affect that relationship
    9·1 answer
  • What is the Sl unit for energy? Be sure to give the full name for the unit
    14·1 answer
  • Please help .....................
    7·1 answer
  • What is the voltage across a 100 ohm circuit element that draws a current of 1 A?
    13·1 answer
  • If the mass of reactants equals 100g, then the mass of the products would be equal to_______?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!