Hello from MrBillDoesMath!
Answer:
5
Discussion:
Consider the expansion of e^x:
e^x = 1 + x + x^2/2 + x^3/6 +...... => replace x by 5t
e^(5t) = 1 + (5t) + (5t)^2/2 + .... => subtract 1 from both sides
e^(5t) - 1 = (5t) + (5t)^2/2+.... => divide both sides by t
(e^(5t) -1)/ t = 5 + (25/2) t +....
so as t ends to 0 the quotient tends to
5 + (25/2)0 + (other terms) *0 -> 5
Thank you,
MrB
The complete question in the attached figure
we know that
[area of a circle]=pi*r²
for r=1 unit
[area of a circle]=pi*1²---------> pi units²
if the area a full circle of 360°--------------> is pi
the area of sector 88°------------------------> X
X=88*pi/360--------> 0.77 units²
the answer is
<span>
the area of sector AOB is 0.77 units</span>
²
Answer:
The answer is C
Step-by-step explanation:
<span>The answer should be 0.00008726567
Hope this helps! </span>
Answer:εδΑΒΓΒΕ
![U4\leq \sqrt{x} \sqrt[n]{x} 64](https://tex.z-dn.net/?f=U4%5Cleq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%2064)
Step-by-step explanation:
73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±