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Cloud [144]
2 years ago
15

Light with a photon energy of 3 ev impinges on the surface of a material with work function 0.6 ev to eject electrons. what is t

he kinetic energy of the outgoing electrons
Physics
1 answer:
DENIUS [597]2 years ago
5 0

Answer:

KE = incident energy - work function

The maximum KE will be (3 - .6) eV = 2.4 eV

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A plastic bottle partially filled with water floats on water, even though the density of the plastic (1.2 g/cc) is more than tha
Semmy [17]

Answer:

True the plastic will float because of the principle of flotation or buoyancy

Explanation:

Buoyancy explains it all!!

Buoyancy  is the upward force/upthrust experienced by a body immersed totally or partially in a liquid.

According to the principle of flotation:

<em>"when a body is totally or partially immersed in liquid it experiences an upthrust which is equal to the volume of fluid displaced"</em>

The plastic will float due to the fact the average density of the total volume of the plastic and the air inside it is less than the same volume of water it is floating in

5 0
3 years ago
Question 2 of 10
Arlecino [84]

Answer:

B: Energy that is transformed is neither created or destroyed

Explanation:

4 0
2 years ago
Lucifer is sitting in a tree that is 15 m above the ground. She jumps straight off the tree in the horizontal direction and land
-BARSIC- [3]

Answer:

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4 0
3 years ago
What distance will a car traveling at a speed of 15 m/s cover in 300 s?
AnnZ [28]

Distance formula: d = st

d = 15 * 300

d = 4,500m

Best of Luck!

3 0
3 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.
Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

6 0
3 years ago
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