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3 years ago

Electromagnetic waves are produced when _____.

Physics

2 answers:

GuDViN [60]3 years ago

8 0

Answer: A

Explanation: when an electric charge accelerates it gains kinetic energy which is then expelled as radiation due to its vibration or acceleration

Tju [1.3M]3 years ago

6 0

Answer: The correct answer is a.

Explanation:

Electromagnetic wave is a wave in which the magnetic field and the electric field are perpendicular to each other.

Both fields are directed in the direction of the propagation of the electromagnetic wave. It travels with the speed of the light.

The motion of the electric field produces both electric field and the magnetic field.

The electromagnetic waves are produced when an electric charge vibrates or accelerates.

Therefore, the correct option is (a).

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Dave wishes to get produce from the store, which is a distance D- 2.2 km east of his house. Dave drives his bike to the store at

Neporo4naja [7]

Answer:

a) $t_1=338.4615\ s$

b) $t=1386.0805\ s$

c) $t=23.1013\ min$

d) $d=4400\ m$

e) Since Dave starts from house and finally returns to the house so displacement is zero.

Explanation:

Given:

distance between the house and the store, $s=2.2\ km=2200\ m$

speed of driving from house to store, $v_1=-6.5\ m.s^{-1}$

speed of driving back from store to house, $v_2=2.1\ m.s^{-1}$

Since the store is located towards east from his house and the velocity in this direction is taken negative and contrary to this the velocity in the west direction is taken positive.

time taken in reaching the store:

$t_1=\frac{s}{v_1}$

$t_1=\frac{-2200}{-6.5}$

$t_1=338.4615\ s$

Now the time taken in returning form the store:

$t_2=\frac{s}{v_2}$

$t_2=\frac{2200}{2.1}$

$t_2=1047.6190\ s$

therefore total time taken by the trip:

$t=t_1+t_2$

$t=338.4615+1047.6190$

$t=1386.0805\ s$

the time taken by the trip in minutes:

$t=\frac{1386.0805}{60}$

$t=23.1013\ min$

distance travelled in the whole trip:

$d=2\times s$

$d=2\times 2200$

$d=4400\ m$

Since Dave starts from house and finally returns to the house so displacement is zero.

3 0

3 years ago

A 10 V battery is connected to a voltage divider circuit

Svetradugi [14.3K]

Answer:

a) C. 7.5 V

b) A. 2.5 V

Explanation:

First, we find the total resistance of the circuit. A voltage divider circuit is a series circuit. Therefore, its total resistance will be the sum of individual resistances:

$R = R_{1}+R_{2}\\R = 100\ \Omega + 300\ \Omega\\R = 400\ \Omega\\$

Now, we will apply the voltage divider rule on this circuit to find the voltage across the 300 Ω Resistor (R₂):

$V_{2} = R_{2}\frac{V}{R}\\\\V_{2} = (300\ \Omega)\frac{10\ V}{400\ \Omega}\\\\$

V₂ = 7.5 V

Therefore, the correct option is:

C. 7.5 V

Now, the voltage across the 100 Ω Resistor (R₁) will be:

$V = V_{1}+V_{2}\\V_{1} = V-V_{2}\\V_{1} = 10\ V - 7.5\ V\\V_{1}=2.5\ V$

Therefore,the correct option is:

A. 2.5 V

5 0

2 years ago

A thin, horizontal copper rod is 1.0792 m long and has a mass of 53.1794 g. The acceleration of gravity is 9.8 m/s 2 . What is t

horsena [70]

Answer:

0.1675 A

Explanation:

Since $BILsin\theta=mg$ then making I the subject $I=\frac {mg}{BLsin\theta}$ where L is the length of the rod, in this case given as 1.0792 m, B is magnetic field which is given as 2.88578 T, m is the mass which is 53.1794 g which is equivalent to 0.0531794 Kg . For minimum current, $sin\theta=1.$

Substituting the given values then

$I=\frac {0.0531794\times 9.81}{1.0792\times 2.88578}=0.167512525 A\approx 0.1675 A$

3 0

3 years ago

A capacitor with C = 6.00 μF is fully charged by connecting it to a battery that has emf 50.0 V. The capacitor is disconnected f

Arte-miy333 [17]

Answer:

1.99×10^-4coulombs

Explanation:

The charge (Q) across the resistor the directly proportional to the voltage (V) where capacitance of the capacitor(C) is the proportionality constant. Mathematically, Q = CV

If V is the voltage across the resistor, V = IR (according to ohm's law) where I is the current in the resistor and R is the resistance.

We need to calculate the voltage on the resistor first when 0.18A current is passed through it.

V = 0.18 × 185

V = 33.3Volts

The charge Q on the resistor will be;

Q = CV

Were C = 6.00 μF, V = 33.3

Q= 6×10^-6 ×33.3

Q = 0.0001998

Q= 1.99×10^-4Coulombs

4 0

2 years ago

Measure of how high or low a sound is

katovenus [111]

PITCH
please mark brainliest!!!

4 0

2 years ago

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