Answer:
....I think you should give us the scenarios first so that we can help you.
I would answer that as Answer D) Checking it’s conductivity
Answer:
Let the "barred" allele be caller B and the "non-white" allele b. Since chickens use chromosomes
and
to determine sex, hens would have chromosomes
, and roosters would have chromosomes
. A Z-linked gene is represented as a superscript on the
chromosome,
for the dominant allele and
for the ressesive allele.
A barred hen would have a copy of B on its Z chromosome, a non-barred rooster would have both copies of b on both Z chromosomes. Using Punnet squares to represent the crosses we get the following cases:

That is a ratio of two barred heterozygote roosters to two non-barred hens. Crossing them we get:

That is a ratio of one barred heterozygote rooster to one barred hen to one non-barred rooster to one non barred hen.
Answer: i think it is domains kingdoms
Explanation: based on their cell types
<span>Ss, Ss, ss, ss will the genotypes formed
So your an
answer is B
hope i helped ;)</span>