<u>Explanation:</u>
Task 1 time period = 200ms, Task 2 time period = 300ms
Task ticked = → 5 times
Task 2 ticked = → 3 times
At 600 ms → 200ms 200ms 200ms
300ms →
Largest time period = H.C.M of (200ms, 300ms)
= 600ms
Using Von Karman momentum integral equation, find the boundary layer thickness, the displacement thickness, the momentum thickne
ss the wall shear stress, the friction coefficient, and the drag coefficient for a flat plate with zero pressure gradient in a laminar flow. Assume a third order polynomial for the velocity profile. What happens is we add a constant positive pressure gradient
1 answer:
You might be interested in
Answer:
Elastic modulus of steel = 202.27 GPa
Explanation:
given data
long = 110 mm = 0.11 m
cross section 22 mm = 0.022 m
load = 89,000 N
elongation = 0.10 mm = 1 × m
solution
we know that Elastic modulus is express as
Elastic modulus = ................1
here stress is
Stress = .................2
Area = (0.022)²
and
Strain = .............3
so here put value in equation 1 we get
Elastic modulus =
Elastic modulus of steel = 202.27 × Pa
Elastic modulus of steel = 202.27 GPa