Answer:
The correct answer will be "DC". The further explanation is given below.
Explanation:
- Ohm's law, that also specifies that perhaps the flow of current via the capacitor is equal to the PD (potential difference) between the opposite edges including its conductor while the heat, as well as the other physical state of that same conductor, stay the very same. Throughout the experiment, this linear change in electrical current with such a PD is better identified by changing the difference unidirectional.
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- The linear or dimensional dependency of current onto PD wasn’t simple and easy to grasp. The supply voltage used would also be DC tube.
Answer: Starting of with Chemical Engineering something that they may encounter is a lack of adeptness man puissance. People that are working there are not much adept or having cognizance regarding to chemical industry. Something someone with a Civil engineering might encounter is the quandary of sustainable construction, and amendment construction site safety. To go on , something that Electrical engineering might encounter is a Non technical , Virtually an electrical engineer has to deal with an astronomical range of machines , control panels,instruments. For example you are working with circuit breakers,as anon as you’ll have expertise on any particular type of circuit breaker, there's a transmutation in trend and the CB you are working with is already obsolete. And last but no least , Something someone might encounter while doing Mechanical engineering is there toxic substances because their work environment is susceptible to fires, explosions, structural failures and equipment malfunctions.
Answer:
True
Explanation:
CLASSIFICATION OF CERAMICS: ceramics can be classified in mainly three categories
- oxides : ceria, zirconia
- non oxide: carbide nitride
- composite materials : combination of oxides and non oxides
PROPERTIES OF CERAMICS :
- High melting point
- high hardness
- great strength
- Low electrical and thermal conductivity( good insulator)
- they are very less reactive with others
- its products are very hard
Answer: 98.5% of pearlite was formed during the equilibrium cooling
Explanation:
First we calculate the fraction of pro-eutectoid phase which forms for equilibrium cooling of the 1085 steel from 1000°C at room temperature;
we know that in 1085 steel, last two digits denotes the carbon percentage
so 1085 steel contains 0.85% carbon.
Now from the diagram, carbon percentage is greater than the eutectoid com[psition
i.e 0.85 > 0.76
it is a hyper eutectoid steel
so
fraction of pro eutectoid phase W_Fe₃C = (0.85 - 0.76) / ( 6.7 - 0.76)
= 0.09 / 5.94 = 0.015 = 1.5%
Now, the amount of pearlite formed during the equilibrium cooling of the 1055 steel from 1000°C to room temperature will be;
pearlite (C') = (1 - W_Fe₃C)
= 1 - 0.015
= 0.985 = 98.5%
Therefore 98.5% of pearlite was formed during the equilibrium cooling
Answer: 383.22K
Explanation:
L = 3m, w = 1.5m
Area A = 3 x 1.5 = 4.5m2
Q' = 750W/m2 (heat from sun) ,
& = 0.87
Q = &Q' = 0. 87x750 = 652.5W/m2
E = QA = 652.5 x 4.5 = 2936.25W
T(sur) = 300K, T(panel) = ?
Using E = §€A(T^4(panel) - T^4(sur))
§ = Stefan constant = 5.7x10^-8
€ = emmisivity = 0.85
2936.25 = 5.7x10^-8 x 0.85 x 4.5 x (T^4(panel) - 300^4)
T(panel) = 383.22K
See image for further details.