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You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3
So, for 2.3 ✕ 10−6 m OH-
[Cu2+] =

Explanation:
1 mol = 22.4 l
5.42 mol = 22.4 × 5.42 = 121.408
in two decimal place it is 121.41
Its FeSO3 or iron(iii)sulfite = Fe2(SO3)3
Answer:
A
Explanation:
0.2g of atom of nitrogen is the one that weigh least cause of.2g is not up to one mole of nitrogen
Answer:
to calculate the molarity of the said sucrose,
firstly calculate the moles
which is = Molecular weight of C12H22O11 = 342g/mol
then
moles = 139/342
= 0.41 moles
to calculate Molarity now
Molarity= moles of the solute/volume of solution in liter
=0.41/2.60
=0.158M
Explanation: