All categories

3 years ago

How many grams of water are produced if we react 3 moles of hydrogen with 3 moles of oxygen?

Chemistry

1 answer:

Thepotemich [5.8K]3 years ago

4 0

Answer:

About 60 grams

Explanation:

The balanced equation of the reaction is given as;

2H2(g) + O2(g) → 2H2O(l)

From the equation;

2 mol of H2 reacts with 1 mol of O2

3 mol of H2 would require 3/2 mol of O2 (considering the 2:1 ratio)

The limiting reactant is H2 as it would be used up before H2. It determines the amount of product that would be formed.

2 mol of H2 produces 2 mol of H2O

3 mol of H2 would produce 3 mol of H2O (Considering the 1 : 1 ratio)

Converting moles to mass;

Mass = Molar mass * Number of moles

Mass = 18 * 3 = 54 g

The correct option is; About 60 grams

You might be interested in

Cameron is visiting a new country while traveling around the world. He is extremely fascinated by the cuisine of this country. H

lina2011 [118]

Not exactly chemistry but ok.

Phó is one of the famous dish in Vietnamese Culture

Hence, the answer is Vietnamese Cuisine

8 0

3 years ago

Read 2 more answers

If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.

vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0

3 years ago

Read 2 more answers

PLS HELP IT IS DUE TODAY IN 30 MINS PLS ANSWER 14 POINTS

Natali5045456 [20]

Answer:

gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

Explanation:

hope that helps! (:

6 0

3 years ago

Read 2 more answers

The two methods in the lab for measuring the volume of a geometric solid object are weighing it on the balance and measuring it

Yakvenalex [24]

Answer:

Measuring with a ruler and using final volume minus initial volume

Explanation:

You can measure the volume of a geometric object by measuring its sides with a ruler and calculating the volume according to the corresponding formula for each object. For example, for a rectangular prism it would be

$volume=length*width*height$

You can also measure the volume of an object by measuring how much water it displaces. To do this you have to fill a measuring cylinder with enough water for the object to be completely submerged and take note of the volume. Then, add the object and note again the volume of the water+object. The difference between both is the volume of the object.

$Volume of the object= volume of water and object - volume of water$